Selesaikan limit (as x approaches 0) of 2/x | Microsoft Math Solver

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5 soal serupa dengan:

x \to 0 lim \frac{2}{x}

Soal yang Mirip dari Pencarian Web

f : R ∖ {0} \to R

f (x) = \frac{1}{x}

lim_{x \to 0} \frac{1}{x}

https://math.stackexchange.com/q/2826102

f : U \to R

is an application defined on a subset

U

R

p

is a real, not necessarily belonging to

U

f

is "defined in the neighborhood of

p

lim_{x \to 0} \frac{x}{[ x ]}

https://math.stackexchange.com/q/2835948

x \to 0

\frac{x}{[ x ]}

is not well defined since for

0 < x < 1

it corresponds to

\frac{x}{0}

and thus we can't calculate the limit for that expression. As you noticed, we can only ...

Disprove the limit

lim_{x \to 0} \frac{1}{x} = 5

with epsilon-delta

https://math.stackexchange.com/q/1527181

ϵ > 0

, we want to find

δ > 0

∣ x - 0 ∣ = ∣ x ∣ < ∣ δ ∣

∣ \frac{1}{x} - 5 ∣ < ϵ

∣ \frac{1}{x} - 5 ∣ = ∣ \frac{1 - 5 x}{x} ∣

so, if x is positive,

∣ \frac{1}{x} - 5 ∣ < ϵ

Is this a valid use of l'Hospital's Rule? Can it be used recursively?

https://math.stackexchange.com/questions/946785/is-this-a-valid-use-of-lhospitals-rule-can-it-be-used-recursively

L'Hôpital's Rule Assuming that the following conditions are true:

f (x)

g (x)

must be differentiable

\frac{d}{d x} g (x) \neq = 0

How to explain that division by

0

yields infinity to a 2nd grader

https://math.stackexchange.com/questions/242258/how-to-explain-that-division-by-0-yields-infinity-to-a-2nd-grader

The first thing to point out is that division by zero is not defined! You cannot divide by zero. Consider the number

1 / x

x

is a negative number. You will find that

1 / x

is negative for all ...

precise definition of a limit at infinity, application for limit at sin(x)

https://math.stackexchange.com/questions/1776133/precise-definition-of-a-limit-at-infinity-application-for-limit-at-sinx

Some items have been dealt with in comments, so we look only at c). We want to show that for any

ϵ > 0

B

x > B

∣ sin (1 / x) - 0 ∣ < ϵ .

ϵ > 0

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x \to - 3 lim \frac{x ^{2} - 9}{x ^{2} + 2 x - 3}