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Daftar
Evaluasi
\sqrt{\frac{2}{x}}
x
2
Diferensial w.r.t. x
-\frac{\sqrt{2}}{2x^{\frac{3}{2}}}
−
2
x
2
3
2
Grafik
Kuis
Algebra
\frac { \sqrt { 2 x } } { x }
x
2
x
Soal yang Mirip dari Pencarian Web
How do you simplify \displaystyle\sqrt{{\frac{{{2}{x}}}{{{9}{x}}}}} ?
How do you simplify
9
x
2
x
?
https://socratic.org/questions/how-do-you-simplify-sqrt-2x-9x
\displaystyle\sqrt{{\frac{{{2}{x}}}{{{9}{x}}}}}=\frac{\sqrt{{{2}}}}{{3}} excluding \displaystyle{x}={0} Explanation: For any positive Real numbers \displaystyle{a},{b} : \displaystyle\sqrt{{\frac{{a}}{{b}}}}=\frac{\sqrt{{{a}}}}{\sqrt{{{b}}}} ...
9
x
2
x
=
3
2
excluding
x
=
0
Explanation: For any positive Real numbers
a
,
b
:
b
a
=
b
a
...
How do you rationalize the denominator and simplify \displaystyle\frac{{6}}{{\sqrt{{{2}{x}}}}} ?
How do you rationalize the denominator and simplify
2
x
6
?
https://socratic.org/questions/how-do-you-rationalize-the-denominator-and-simplify-6-sqrt-2x
\displaystyle\frac{{{3}\sqrt{{{2}{x}}}}}{{x}} Explanation: \displaystyle\frac{{6}}{{\sqrt{{{2}{x}}}}} \displaystyle\frac{{6}}{{\sqrt{{{2}{x}}}}}\cdot{\left[\frac{{\cancel{-}\sqrt{{{2}{x}}}}}{{\cancel{{-}}\sqrt{{{2}{x}}}}}\right]} ...
x
3
2
x
Explanation:
2
x
6
2
x
6
⋅
[
−
2
x
−
2
x
]
...
How do you solve \displaystyle\frac{{x}}{{2}}=\sqrt{{{x}-{1}}} ?
How do you solve
2
x
=
x
−
1
?
https://socratic.org/questions/how-do-you-solve-x-2-sqrt-x-1
\displaystyle{x}={2} Explanation: First, start by taking a look at the equation \displaystyle\sqrt{{{x}-{1}}}=\frac{{x}}{{2}} Right from the start, you need \displaystyle{x} to be ...
x
=
2
Explanation: First, start by taking a look at the equation
x
−
1
=
2
x
Right from the start, you need
x
to be ...
How do you solve \displaystyle\frac{\sqrt{{{2}{x}}}}{{5}}={6} ?
How do you solve
5
2
x
=
6
?
https://socratic.org/questions/how-do-you-solve-sqrt-2x-5-6
450 Explanation: \displaystyle\frac{\sqrt{{{2}{x}}}}{{5}}={6} \displaystyle\sqrt{{{2}{x}}}={30} \displaystyle{2}{x}={30}^{{2}} \displaystyle{2}{x}={900} \displaystyle{x}={450}
450 Explanation:
5
2
x
=
6
2
x
=
3
0
2
x
=
3
0
2
2
x
=
9
0
0
x
=
4
5
0
Integral of \sqrt{\frac{x}{x+1}}
Integral of
x
+
1
x
https://math.stackexchange.com/q/2588817
If you consider y=\sqrt{x(x+1)}, then y^2=x^2+x=(x+1/2)^2-1/4 or \left(x+\frac{1}{2}\right)^{\!2}-y^2=\frac{1}{4} which suggests making the substitution x+\frac{1}{2}=\frac{1}{2}\cosh t \qquad y=\frac{1}{2}\sinh t \qquad dx=\frac{1}{2}\sinh t\,dt ...
If you consider
y
=
x
(
x
+
1
)
, then
y
2
=
x
2
+
x
=
(
x
+
1
/
2
)
2
−
1
/
4
or
(
x
+
2
1
)
2
−
y
2
=
4
1
which suggests making the substitution
x
+
2
1
=
2
1
cosh
t
y
=
2
1
sinh
t
d
x
=
2
1
sinh
t
d
t
...
What is the limit of \displaystyle\frac{{\sqrt{{x}}}}{{{x}+{4}}} as x approaches infinity?
What is the limit of
x
+
4
x
as x approaches infinity?
https://socratic.org/questions/what-is-the-limit-of-sqrt-x-x-4-as-x-approaches-infinity
0 Explanation: \displaystyle\lim\to infinity of the ratio of \displaystyle\frac{{x}^{{m}}}{{x}^{{n}}} is 0 or infinity, according as, when m < or < n. . Divide by \displaystyle\sqrt{{x}} ...
0 Explanation:
lim
→
infinity of the ratio of
x
n
x
m
is 0 or infinity, according as, when m < or < n. . Divide by
x
...
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Persamaan kuadrat
{ x } ^ { 2 } - 4 x - 5 = 0
x
2
−
4
x
−
5
=
0
Trigonometri
4 \sin \theta \cos \theta = 2 \sin \theta
4
sin
θ
cos
θ
=
2
sin
θ
Persamaan linear
y = 3x + 4
y
=
3
x
+
4
Aritmetika
699 * 533
6
9
9
∗
5
3
3
Matriks
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
[
2
5
3
4
]
[
2
−
1
0
1
3
5
]
Persamaan simultan
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
{
8
x
+
2
y
=
4
6
7
x
+
3
y
=
4
7
Diferensial
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
d
x
d
(
x
−
5
)
(
3
x
2
−
2
)
Integral
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
∫
0
1
x
e
−
x
2
d
x
Limit
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}
x
→
−
3
lim
x
2
+
2
x
−
3
x
2
−
9
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