Լուծեք {l}{A^2+B^2=LB}{2A+B=3X}

$$\left\{ \begin{array} { l } { A ^ { 2 } + B ^ { 2 } = L B } \\ { 2 A + B = 3 X } \end{array} \right.$$

Լուծել A, B, L, X-ի համար (complex solution)

$$A=\frac{3X-B}{2}\text{, }B=\frac{2\sqrt{L^{2}+3LX-9X^{2}}+2L+3X}{5}\text{, }L\in \mathrm{C}\text{, }X\in \mathrm{C}$$

$$A=\frac{3X-B}{2}\text{, }B=\frac{-2\sqrt{L^{2}+3LX-9X^{2}}+2L+3X}{5}\text{, }L\in \mathrm{C}\text{, }X\in \mathrm{C}$$

Լուծել A, B, L, X-ի համար

$$\left\{\begin{matrix}A=\frac{3X-B}{2}\text{, }B=\frac{2\sqrt{L^{2}+3LX-9X^{2}}+2L+3X}{5}\text{, }L\in \mathrm{R}\text{, }X\in \begin{bmatrix}\frac{\sqrt{5}L+L}{6},\frac{-\sqrt{5}L+L}{6}\end{bmatrix}\text{; }A=\frac{3X-B}{2}\text{, }B=\frac{-2\sqrt{L^{2}+3LX-9X^{2}}+2L+3X}{5}\text{, }L\in \mathrm{R}\text{, }X\in \begin{bmatrix}\frac{\sqrt{5}L+L}{6},\frac{-\sqrt{5}L+L}{6}\end{bmatrix}\text{, }&L\leq 0\\A=\frac{3X-B}{2}\text{, }B=\frac{2\sqrt{L^{2}+3LX-9X^{2}}+2L+3X}{5}\text{, }L\in \mathrm{R}\text{, }X\geq \frac{\sqrt{5}L+L}{6}\text{; }A=\frac{3X-B}{2}\text{, }B=\frac{-2\sqrt{L^{2}+3LX-9X^{2}}+2L+3X}{5}\text{, }L\in \mathrm{R}\text{, }X\geq \frac{\sqrt{5}L+L}{6}\text{, }&L>0\\A=\frac{3X-B}{2}\text{, }B=\frac{2\sqrt{L^{2}+3LX-9X^{2}}+2L+3X}{5}\text{, }L\in \mathrm{R}\text{, }X\in \mathrm{R}\text{; }A=\frac{3X-B}{2}\text{, }B=\frac{-2\sqrt{L^{2}+3LX-9X^{2}}+2L+3X}{5}\text{, }L\in \mathrm{R}\text{, }X\in \mathrm{R}\text{, }&L\neq 0\\A=\frac{3X-B}{2}\text{, }B=\frac{2\sqrt{L^{2}+3LX-9X^{2}}+2L+3X}{5}\text{, }L\in \mathrm{R}\text{, }X\in \begin{bmatrix}\frac{-\sqrt{5}L+L}{6},\frac{\sqrt{5}L+L}{6}\end{bmatrix}\text{; }A=\frac{3X-B}{2}\text{, }B=\frac{-2\sqrt{L^{2}+3LX-9X^{2}}+2L+3X}{5}\text{, }L\in \mathrm{R}\text{, }X\in \begin{bmatrix}\frac{-\sqrt{5}L+L}{6},\frac{\sqrt{5}L+L}{6}\end{bmatrix}\text{, }&L\geq 0\\A=\frac{3X-B}{2}\text{, }B=\frac{2\sqrt{L^{2}+3LX-9X^{2}}+2L+3X}{5}\text{, }L\in \mathrm{R}\text{, }X\geq \frac{-\sqrt{5}L+L}{6}\text{; }A=\frac{3X-B}{2}\text{, }B=\frac{-2\sqrt{L^{2}+3LX-9X^{2}}+2L+3X}{5}\text{, }L\in \mathrm{R}\text{, }X\geq \frac{-\sqrt{5}L+L}{6}\text{, }&L<0\end{matrix}\right.$$