{l}{{(x-4)}+8=4/x^2-4x}{y=x}{z=y}{a=z}{b=a}{text{Solvefor}ctext{where}}{c=b} का समाधान करें

$$\left. \begin{array} { l } { {(x - 4)} + 8 = \frac{4}{x ^ {2} - 4 x} }\\ { y = x }\\ { z = y }\\ { a = z }\\ { b = a }\\ { \text{Solve for } c \text{ where} } \\ { c = b } \end{array} \right.$$

x, y, z, a, b, c के लिए हल करें

$$x=\frac{8\sqrt{3}\cos(\frac{\arccos(\frac{3\sqrt{3}}{32})}{3})}{3}\approx 4.11958394\text{, }y=\frac{8\sqrt{3}\cos(\frac{\arccos(\frac{3\sqrt{3}}{32})}{3})}{3}\approx 4.11958394\text{, }z=\frac{8\sqrt{3}\cos(\frac{\arccos(\frac{3\sqrt{3}}{32})}{3})}{3}\approx 4.11958394\text{, }a=\frac{8\sqrt{3}\cos(\frac{\arccos(\frac{3\sqrt{3}}{32})}{3})}{3}\approx 4.11958394\text{, }b=\frac{8\sqrt{3}\cos(\frac{\arccos(\frac{3\sqrt{3}}{32})}{3})}{3}\approx 4.11958394\text{, }c=\frac{8\sqrt{3}\cos(\frac{\arccos(\frac{3\sqrt{3}}{32})}{3})}{3}\approx 4.11958394$$

$$x=\frac{4\left(-\sqrt{3}\cos(\frac{\arccos(\frac{3\sqrt{3}}{32})}{3})-3\sin(\frac{\arccos(\frac{3\sqrt{3}}{32})}{3})\right)}{3}\approx -3.868595752\text{, }y=\frac{4\left(-\sqrt{3}\cos(\frac{\arccos(\frac{3\sqrt{3}}{32})}{3})-3\sin(\frac{\arccos(\frac{3\sqrt{3}}{32})}{3})\right)}{3}\approx -3.868595752\text{, }z=\frac{4\left(-\sqrt{3}\cos(\frac{\arccos(\frac{3\sqrt{3}}{32})}{3})-3\sin(\frac{\arccos(\frac{3\sqrt{3}}{32})}{3})\right)}{3}\approx -3.868595752\text{, }a=\frac{4\left(-\sqrt{3}\cos(\frac{\arccos(\frac{3\sqrt{3}}{32})}{3})-3\sin(\frac{\arccos(\frac{3\sqrt{3}}{32})}{3})\right)}{3}\approx -3.868595752\text{, }b=\frac{4\left(-\sqrt{3}\cos(\frac{\arccos(\frac{3\sqrt{3}}{32})}{3})-3\sin(\frac{\arccos(\frac{3\sqrt{3}}{32})}{3})\right)}{3}\approx -3.868595752\text{, }c=\frac{4\left(-\sqrt{3}\cos(\frac{\arccos(\frac{3\sqrt{3}}{32})}{3})-3\sin(\frac{\arccos(\frac{3\sqrt{3}}{32})}{3})\right)}{3}\approx -3.868595752$$

$$x=\frac{4\sqrt{3}\left(\sqrt{3}\sin(\frac{\arccos(\frac{3\sqrt{3}}{32})}{3})-\cos(\frac{\arccos(\frac{3\sqrt{3}}{32})}{3})\right)}{3}\approx -0.250988189\text{, }y=\frac{4\sqrt{3}\left(\sqrt{3}\sin(\frac{\arccos(\frac{3\sqrt{3}}{32})}{3})-\cos(\frac{\arccos(\frac{3\sqrt{3}}{32})}{3})\right)}{3}\approx -0.250988189\text{, }z=\frac{4\sqrt{3}\left(\sqrt{3}\sin(\frac{\arccos(\frac{3\sqrt{3}}{32})}{3})-\cos(\frac{\arccos(\frac{3\sqrt{3}}{32})}{3})\right)}{3}\approx -0.250988189\text{, }a=\frac{4\sqrt{3}\left(\sqrt{3}\sin(\frac{\arccos(\frac{3\sqrt{3}}{32})}{3})-\cos(\frac{\arccos(\frac{3\sqrt{3}}{32})}{3})\right)}{3}\approx -0.250988189\text{, }b=\frac{4\sqrt{3}\left(\sqrt{3}\sin(\frac{\arccos(\frac{3\sqrt{3}}{32})}{3})-\cos(\frac{\arccos(\frac{3\sqrt{3}}{32})}{3})\right)}{3}\approx -0.250988189\text{, }c=\frac{4\sqrt{3}\left(\sqrt{3}\sin(\frac{\arccos(\frac{3\sqrt{3}}{32})}{3})-\cos(\frac{\arccos(\frac{3\sqrt{3}}{32})}{3})\right)}{3}\approx -0.250988189$$