y=1(1+P/100)^x ઉકેલો

$$y = 1 ( 1 + \frac { P } { 100 } ) ^ { x }$$

P માટે ઉકેલો (જટિલ સમાધાન)

$$P=e^{\frac{Im(x)arg(y)+iRe(x)arg(y)}{\left(Re(x)\right)^{2}+\left(Im(x)\right)^{2}}-\frac{2\pi n_{1}iRe(x)}{\left(Re(x)\right)^{2}+\left(Im(x)\right)^{2}}-\frac{2\pi n_{1}Im(x)}{\left(Re(x)\right)^{2}+\left(Im(x)\right)^{2}}}\left(|y|\right)^{\frac{Re(x)-iIm(x)}{\left(Re(x)\right)^{2}+\left(Im(x)\right)^{2}}}$$

$$n_{1}\in \mathrm{Z}$$

x માટે ઉકેલો (જટિલ સમાધાન)

$$\left\{\begin{matrix}x=\frac{2\pi n_{1}i}{\ln(\frac{P+100}{100})}+\log_{\frac{P+100}{100}}\left(y\right)\text{, }n_{1}\in \mathrm{Z}\text{, }&y\neq 0\text{ and }P\neq 0\text{ and }P\neq -100\\x\in \mathrm{C}\text{, }&\left(P=-100\text{ and }y=0\right)\text{ or }\left(P=0\text{ and }y=1\right)\end{matrix}\right.$$

x માટે ઉકેલો

$$\left\{\begin{matrix}x=\log_{\frac{P+100}{100}}\left(y\right)\text{, }&y>0\text{ and }P\neq 0\text{ and }P>-100\\x\in \mathrm{R}\text{, }&\left(P=0\text{ and }y=1\right)\text{ or }\left(P=-200\text{ and }y=-1\text{ and }Denominator(x)\text{bmod}2=1\text{ and }Numerator(x)\text{bmod}2=1\right)\\x>0\text{, }&P=-100\text{ and }y=0\end{matrix}\right.$$