x=(6a^-1b^3)^-2= ઉકેલો

$$x = ( 6 a ^ { - 1 } b ^ { 3 } ) ^ { - 2 } =$$

a માટે ઉકેલો (જટિલ સમાધાન)

$$a=-6\sqrt{x}b^{3}$$

$$a=6\sqrt{x}b^{3}\text{, }x\neq 0\text{ and }b\neq 0$$

b માટે ઉકેલો (જટિલ સમાધાન)

$$b\in \frac{6^{\frac{2}{3}}x^{-\frac{1}{6}}\sqrt[3]{a}}{6},\frac{6^{\frac{2}{3}}e^{\frac{4\pi i}{3}}x^{-\frac{1}{6}}\sqrt[3]{a}}{6},\frac{6^{\frac{2}{3}}e^{\frac{2\pi i}{3}}x^{-\frac{1}{6}}\sqrt[3]{a}}{6},\frac{6^{\frac{2}{3}}e^{\frac{5\pi i}{3}}x^{-\frac{1}{6}}\sqrt[3]{a}}{6},\frac{6^{\frac{2}{3}}e^{\frac{\pi i}{3}}x^{-\frac{1}{6}}\sqrt[3]{a}}{6},-\frac{6^{\frac{2}{3}}x^{-\frac{1}{6}}\sqrt[3]{a}}{6}$$

$$a\neq 0\text{ and }x\neq 0$$

a માટે ઉકેલો

$$a=6\sqrt{x}b^{3}$$

$$a=-6\sqrt{x}b^{3}\text{, }b\neq 0\text{ and }x>0$$

b માટે ઉકેલો

$$b=\frac{6^{\frac{2}{3}}\sqrt[3]{a}}{6\sqrt[6]{x}}$$

$$b=-\frac{6^{\frac{2}{3}}\sqrt[3]{a}}{6\sqrt[6]{x}}\text{, }a\neq 0\text{ and }x>0$$