V=1/4pid^2h ઉકેલો

$$V = \frac { 1 } { 4 } \pi d ^ { 2 } h$$

d માટે ઉકેલો (જટિલ સમાધાન)

$$\left\{\begin{matrix}d=-2\left(\pi h\right)^{-\frac{1}{2}}\sqrt{V}\text{; }d=2\left(\pi h\right)^{-\frac{1}{2}}\sqrt{V}\text{, }&h\neq 0\\d\in \mathrm{C}\text{, }&V=0\text{ and }h=0\end{matrix}\right.$$

V માટે ઉકેલો

$$V=\frac{\pi hd^{2}}{4}$$

d માટે ઉકેલો

$$\left\{\begin{matrix}d=2\sqrt{\frac{V}{\pi h}}\text{; }d=-2\sqrt{\frac{V}{\pi h}}\text{, }&\left(V\geq 0\text{ and }h>0\right)\text{ or }\left(V\leq 0\text{ and }h<0\right)\\d\in \mathrm{R}\text{, }&V=0\text{ and }h=0\end{matrix}\right.$$