{l}{4x^2-4mx+m+2=0}{Delta=16m^2-32mgeq0} ઉકેલો

$$\left. \begin{array} { l } { 4 x ^ { 2 } - 4 m x + m + 2 = 0 } \\ { \Delta = 16 m ^ { 2 } - 32 m \geq 0 } \end{array} \right.$$

x માટે ઉકેલો (જટિલ સમાધાન)

$$x=\frac{\sqrt{\left(m-2\right)\left(m+1\right)}+m}{2}$$

$$x=\frac{-\sqrt{\left(m-2\right)\left(m+1\right)}+m}{2}\text{, }\Delta =16m\left(m-2\right)$$

x માટે ઉકેલો

$$x=\frac{\sqrt{\left(m-2\right)\left(m+1\right)}+m}{2}$$

$$x=\frac{-\sqrt{\left(m-2\right)\left(m+1\right)}+m}{2}\text{, }\left(m\leq -1\text{ or }m\geq 2\right)\text{ and }\Delta =16m\left(m-2\right)$$