{l}{sin3/5quadcosbeta=-5/13}{sin(a+7)=32} ઉકેલો

$$\left. \begin{array} { l } { \sin \frac { 3 } { 5 } \quad \cos \beta = - \frac { 5 } { 13 } } \\ { \sin ( a + 7 ) = 32 } \end{array} \right.$$

β, a માટે ઉકેલો

$$\beta =2\pi n_{1}-i\ln(\frac{\sqrt{24395964603148870561481014759128391}+156250000000000000}{4254162297224853})+\pi \text{, }n_{1}\in \mathrm{Z}\text{, }a=2\pi n_{2}-i\ln(-i\sqrt{1023}+32i)-7\text{, }n_{2}\in \mathrm{Z}$$

$$\beta =2\pi n_{1}-i\ln(\frac{\sqrt{24395964603148870561481014759128391}+156250000000000000}{4254162297224853})+\pi \text{, }n_{1}\in \mathrm{Z}\text{, }a=2\pi n_{3}-i\ln(i\sqrt{1023}+32i)-7\text{, }n_{3}\in \mathrm{Z}$$

$$\beta =2\pi n_{4}-i\ln(\frac{156250000000000000-\sqrt{24395964603148870561481014759128391}}{4254162297224853})+\pi \text{, }n_{4}\in \mathrm{Z}\text{, }a=2\pi n_{2}-i\ln(-i\sqrt{1023}+32i)-7\text{, }n_{2}\in \mathrm{Z}$$

$$\beta =2\pi n_{4}-i\ln(\frac{156250000000000000-\sqrt{24395964603148870561481014759128391}}{4254162297224853})+\pi \text{, }n_{4}\in \mathrm{Z}\text{, }a=2\pi n_{3}-i\ln(i\sqrt{1023}+32i)-7\text{, }n_{3}\in \mathrm{Z}$$