{l}{y^{2}+x^{3}=c}{y^{2}+frac{x^{2}}{2}=c}{z={(y^2+x^3-c)}{(y^2+x^2/2-c)}}{a=z}{b=a}{text{Solvefor}dtext{where}}{d=b} ઉકેલો

$$\left. \begin{array} { l } { y ^ {2} + x ^ {3} = c }\\ { y ^ {2} + \frac{x ^ {2}}{2} = c }\\ { z = {(y ^ {2} + x ^ {3} - c)} {(y ^ {2} + \frac{x ^ {2}}{2} - c)} }\\ { a = z }\\ { b = a }\\ { \text{Solve for } d \text{ where} } \\ { d = b } \end{array} \right.$$

x, y, z માટે ઉકેલો

$$\left\{\begin{matrix}x=\frac{1}{2}=0.5\text{, }y=-\frac{\sqrt{16c-2}}{4}\text{, }z=0\text{; }x=\frac{1}{2}=0.5\text{, }y=\frac{\sqrt{16c-2}}{4}\text{, }z=0\text{, }&c\geq \frac{1}{8}\text{ and }b=0\text{ and }a=0\text{ and }d=0\\x=0\text{, }y=-\sqrt{c}\text{, }z=0\text{; }x=0\text{, }y=\sqrt{c}\text{, }z=0\text{, }&c\geq 0\text{ and }b=0\text{ and }a=0\text{ and }d=0\end{matrix}\right.$$