{l}{{(1+i/1-i)}^m=1}{j=2}{k=j}{l=k}{n=l}{o=n}{p=o}{q=p}{r=q}{s=r}{text{Solvefor}ttext{where}}{t=s} ઉકેલો

\left. \begin{array} { l } { {(\frac{1 + i}{1 - i})} ^ {m} = 1 }\\ { j = 2 }\\ { k = j }\\ { l = k }\\ { n = l }\\ { o = n }\\ { p = o }\\ { q = p }\\ { r = q }\\ { s = r }\\ { \text{Solve for } t \text{ where} } \\ { t = s } \end{array} \right.

m, j, k, l, n, o, p, q, r, s, t માટે ઉકેલો

t=2

ક્વિઝ

Complex Number

આના જેવા 5 પ્રશ્ન:

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How can 1=\frac{ord\: a}{gcd(ord\:a,k)}|\frac{k}{gcd(ord\:a,k)}?

https://math.stackexchange.com/questions/2530700/how-can-1-fracord-agcdord-a-k-frackgcdord-a-k

You may find the following easier to understand. Let |a| represents the order of a and let the g.c.d. of |a| and k be g. (a^k)^\frac{|a|}{g}=(a^{|a|})^\frac{k}{g}=e and so |a^k| ...

For which values of a,b\in\mathbb{R} does the matrix have no solutions, one solution and infinite solutions.

https://math.stackexchange.com/questions/2018447/for-which-values-of-a-b-in-mathbbr-does-the-matrix-have-no-solutions-one-so

First swap the first and second row. Then by subtracting the first and the second row from the third one and then subtracting a times the first row from the second we get: \left(\begin{array}{ccc|c} 1& a& 3 & b\\ 0 & 4-a^2 & -2a & -ab \\ 0 & 0 & -b^2-3 & -2 \end{array}\right) ...

How to prove this equation with Bessel function and Laguerre function?

https://math.stackexchange.com/questions/2541322/how-to-prove-this-equation-with-bessel-function-and-laguerre-function

Coordinate matrix of a vector in terms of a basis

https://math.stackexchange.com/questions/108389/coordinate-matrix-of-a-vector-in-terms-of-a-basis

(I'll do it for dimension n because the difficulty is the same) Suppose you write \{e_1,\ldots,e_n\} for the canonical basis (could be any basis, actually), and let \{f_1,\ldots,f_n\} be another ...

If a_n = \frac{{(n + 1)}^n}{n^{n - 1}} and c > 0 then \lim_{n \to \infty} n^{1-c}(a^c_n-a^c_{n-1}) =ce^c

https://math.stackexchange.com/questions/2259452/if-a-n-fracn-1nnn-1-and-c-0-then-lim-n-to-infty

I think the approach in my answer to the question which you have linked should work without much change. To simplify typing I will use A = a_{n}, B = a_{n - 1}. Note that A/n, B/n \to e. I first ...

Showing positive definiteness in the projection of ellipsoid

https://math.stackexchange.com/questions/2438495/showing-positive-definiteness-in-the-projection-of-ellipsoid

First of all, a graphical illustration (Matlab program given below). Answer to the question "Why is B an spd (symmetric positive definite) matrix ?" It is because \mathbf{B} can be written, in a ...

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દ્વિઘાત સમીકરણ

{ x } ^ { 2 } - 4 x - 5 = 0

ત્રિકોણમિતિ

4 \sin \theta \cos \theta = 2 \sin \theta

\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]

યુગપત્ સમીકરણ

\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.

ડિફરેન્શિએશન

\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }

ઇન્ટિગ્રેશન

\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x

લિમિટ્સ

\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}

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