Resolver 9(20*10^-8)*(02*10^-4)

$$9 ( 20 \times 10 ^ { - 8 } ) \times ( 02 \times 10 ^ { - 4 } )$$

Calcular

$$0$$

Pasos da solución

Para multiplicar potencias da mesma base, suma os seus expoñentes. Suma -8 e -4 para obter -12.

$$9\times 20\times 10^{-12}\times 0\times 2$$

Multiplica 9 e 20 para obter 180.

$$180\times 10^{-12}\times 0\times 2$$

Calcula 10 á potencia de -12 e obtén \frac{1}{1000000000000}.

$$180\times \frac{1}{1000000000000}\times 0\times 2$$

Multiplica 180 e \frac{1}{1000000000000} para obter \frac{9}{50000000000}.

$$\frac{9}{50000000000}\times 0\times 2$$

Multiplica \frac{9}{50000000000} e 0 para obter 0.

$$0\times 2$$

Multiplica 0 e 2 para obter 0.

$$0$$

Factorizar

$$0$$