Resolver 75*[2*(1-03-05)+3*(06-05+010)]

$$75 \cdot [ 2 \cdot ( 1 - 03 - 05 ) + 3 \cdot ( 06 - 05 + 010 ) ]$$

Calcular

$$150$$

Pasos da solución

Multiplica 0 e 3 para obter 0.

$$75\left(2\left(1-0-0\times 5\right)+3\left(0\times 6-0\times 5+0\times 10\right)\right)$$

Resta 0 de 1 para obter 1.

$$75\left(2\left(1-0\times 5\right)+3\left(0\times 6-0\times 5+0\times 10\right)\right)$$

Multiplica 0 e 5 para obter 0.

$$75\left(2\left(1-0\right)+3\left(0\times 6-0\times 5+0\times 10\right)\right)$$

Resta 0 de 1 para obter 1.

$$75\left(2\times 1+3\left(0\times 6-0\times 5+0\times 10\right)\right)$$

Multiplica 2 e 1 para obter 2.

$$75\left(2+3\left(0\times 6-0\times 5+0\times 10\right)\right)$$

Multiplica 0 e 6 para obter 0.

$$75\left(2+3\left(0-0\times 5+0\times 10\right)\right)$$

Multiplica 0 e 5 para obter 0.

$$75\left(2+3\left(0-0+0\times 10\right)\right)$$

Se restas 0 a si mesmo, quédache 0.

$$75\left(2+3\left(0+0\times 10\right)\right)$$

Multiplica 0 e 10 para obter 0.

$$75\left(2+3\left(0+0\right)\right)$$

Suma 0 e 0 para obter 0.

$$75\left(2+3\times 0\right)$$

Multiplica 3 e 0 para obter 0.

$$75\left(2+0\right)$$

Suma 2 e 0 para obter 2.

$$75\times 2$$

Multiplica 75 e 2 para obter 150.

$$150$$

Factorizar

$$2\times 3\times 5^{2}$$