Resolver 4s^2(-5u)=(3t-4(3)/5)

$$4 s ^ { 2 } ( - 5 u ) = ( \frac { 3 t - 4 ( 3 ) } { 5 } )$$

Resolver t

$$t=-\frac{100us^{2}}{3}+4$$

Pasos para resolver unha ecuación lineal

Multiplica ambos lados da ecuación por 5.

$$20s^{2}\left(-5\right)u=3t-4\times 3$$

Multiplica 20 e -5 para obter -100.

$$-100s^{2}u=3t-4\times 3$$

Multiplica 4 e 3 para obter 12.

$$-100s^{2}u=3t-12$$

Cambia de lado para que todos os termos variables estean no lado esquerdo.

$$3t-12=-100s^{2}u$$

Engadir 12 en ambos lados.

$$3t=-100s^{2}u+12$$

A ecuación está en forma estándar.

$$3t=12-100us^{2}$$

Divide ambos lados entre 3.

$$\frac{3t}{3}=\frac{12-100us^{2}}{3}$$

A división entre 3 desfai a multiplicación por 3.

$$t=\frac{12-100us^{2}}{3}$$

Divide -100s^{2}u+12 entre 3.

$$t=-\frac{100us^{2}}{3}+4$$

Resolver s (complex solution)

$$\left\{\begin{matrix}s=-\frac{iu^{-\frac{1}{2}}\sqrt{3\left(t-4\right)}}{10}\text{; }s=\frac{iu^{-\frac{1}{2}}\sqrt{3\left(t-4\right)}}{10}\text{, }&u\neq 0\\s\in \mathrm{C}\text{, }&t=4\text{ and }u=0\end{matrix}\right.$$

Resolver s

$$\left\{\begin{matrix}s=\frac{\sqrt{-\frac{3\left(t-4\right)}{u}}}{10}\text{; }s=-\frac{\sqrt{-\frac{3\left(t-4\right)}{u}}}{10}\text{, }&\left(u>0\text{ and }t\leq 4\right)\text{ or }\left(t\geq 4\text{ and }u<0\right)\\s\in \mathrm{R}\text{, }&t=4\text{ and }u=0\end{matrix}\right.$$