Resolver (624*10^-2)+(71*10^-3)

$$( 624 \times 10 ^ { - 2 } ) + ( 71 \times 10 ^ { - 3 } )$$

Calcular

$$\frac{6311}{1000}=6.311$$

Pasos da solución

Calcula 10 á potencia de -2 e obtén \frac{1}{100}.

$$624\times \frac{1}{100}+71\times 10^{-3}$$

Multiplica 624 e \frac{1}{100} para obter \frac{156}{25}.

$$\frac{156}{25}+71\times 10^{-3}$$

Calcula 10 á potencia de -3 e obtén \frac{1}{1000}.

$$\frac{156}{25}+71\times \frac{1}{1000}$$

Multiplica 71 e \frac{1}{1000} para obter \frac{71}{1000}.

$$\frac{156}{25}+\frac{71}{1000}$$

Suma \frac{156}{25} e \frac{71}{1000} para obter \frac{6311}{1000}.

$$\frac{6311}{1000}$$

Factorizar

$$\frac{6311}{2 ^ {3} \cdot 5 ^ {3}} = 6\frac{311}{1000} = 6.311$$