Resolver (3^{3}-2*9):3+{[(4^{3}-2*7-2^2*5):10]^2+1}:5+4^2-7^0

$$( 3 ^ { 3 } - 2 \times 9 ) : 3 + \{ [ ( 4 ^ { 3 } - 2 \times 7 - 2 ^ { 2 } \times 5 ) : 10 ] ^ { 2 } + 1 \} : 5 + 4 ^ { 2 } - 7 ^ { 0 }$$

Calcular

$$20$$

Pasos da solución

Calcula 3 á potencia de 3 e obtén 27.

$$\frac{27-2\times 9}{3}+\frac{\left(\frac{4^{3}-2\times 7-2^{2}\times 5}{10}\right)^{2}+1}{5}+4^{2}-7^{0}$$

Multiplica 2 e 9 para obter 18.

$$\frac{27-18}{3}+\frac{\left(\frac{4^{3}-2\times 7-2^{2}\times 5}{10}\right)^{2}+1}{5}+4^{2}-7^{0}$$

Resta 18 de 27 para obter 9.

$$\frac{9}{3}+\frac{\left(\frac{4^{3}-2\times 7-2^{2}\times 5}{10}\right)^{2}+1}{5}+4^{2}-7^{0}$$

Divide 9 entre 3 para obter 3.

$$3+\frac{\left(\frac{4^{3}-2\times 7-2^{2}\times 5}{10}\right)^{2}+1}{5}+4^{2}-7^{0}$$

Calcula 4 á potencia de 3 e obtén 64.

$$3+\frac{\left(\frac{64-2\times 7-2^{2}\times 5}{10}\right)^{2}+1}{5}+4^{2}-7^{0}$$

Multiplica 2 e 7 para obter 14.

$$3+\frac{\left(\frac{64-14-2^{2}\times 5}{10}\right)^{2}+1}{5}+4^{2}-7^{0}$$

Resta 14 de 64 para obter 50.

$$3+\frac{\left(\frac{50-2^{2}\times 5}{10}\right)^{2}+1}{5}+4^{2}-7^{0}$$

Calcula 2 á potencia de 2 e obtén 4.

$$3+\frac{\left(\frac{50-4\times 5}{10}\right)^{2}+1}{5}+4^{2}-7^{0}$$

Multiplica 4 e 5 para obter 20.

$$3+\frac{\left(\frac{50-20}{10}\right)^{2}+1}{5}+4^{2}-7^{0}$$

Resta 20 de 50 para obter 30.

$$3+\frac{\left(\frac{30}{10}\right)^{2}+1}{5}+4^{2}-7^{0}$$

Divide 30 entre 10 para obter 3.

$$3+\frac{3^{2}+1}{5}+4^{2}-7^{0}$$

Calcula 3 á potencia de 2 e obtén 9.

$$3+\frac{9+1}{5}+4^{2}-7^{0}$$

Suma 9 e 1 para obter 10.

$$3+\frac{10}{5}+4^{2}-7^{0}$$

Divide 10 entre 5 para obter 2.

$$3+2+4^{2}-7^{0}$$

Suma 3 e 2 para obter 5.

$$5+4^{2}-7^{0}$$

Calcula 4 á potencia de 2 e obtén 16.

$$5+16-7^{0}$$

Suma 5 e 16 para obter 21.

$$21-7^{0}$$

Calcula 7 á potencia de 0 e obtén 1.

$$21-1$$

Resta 1 de 21 para obter 20.

$$20$$

Factorizar

$$2^{2}\times 5$$