Resolver {r}{(1/3)^{8}+8*(2/3)(1/3)^{7}+8!/6!2!(frac{2}{3})^{2}(frac{1}{3})^{6}+frac{8!}{5!3!}(frac{2}{3})^{3}(frac{1}{3})^{5}+frac{8!}{4!4!}(frac{2}{3})^4(frac{1}{3})^4}{quad+frac{8!}{3!5!}(frac{2}{3})^5(frac{1}{3})^3}

$$\left. \begin{array} { r } { ( \frac { 1 } { 3 } ) ^ { 8 } + 8 \cdot ( \frac { 2 } { 3 } ) ( \frac { 1 } { 3 } ) ^ { 7 } + \frac { 8 ! } { 6 ! 2 ! } ( \frac { 2 } { 3 } ) ^ { 2 } ( \frac { 1 } { 3 } ) ^ { 6 } + \frac { 8 ! } { 5 ! 3 ! } ( \frac { 2 } { 3 } ) ^ { 3 } ( \frac { 1 } { 3 } ) ^ { 5 } + \frac { 8 ! } { 4 ! 4 ! } ( \frac { 2 } { 3 } ) ^ { 4 } ( \frac { 1 } { 3 } ) ^ { 4 } } \\ { \quad + \frac { 8 ! } { 3 ! 5 ! } ( \frac { 2 } { 3 } ) ^ { 5 } ( \frac { 1 } { 3 } ) ^ { 3 } } \end{array} \right.$$

Calcular

$$\frac{1163}{2187}\approx 0.531778692$$

Pasos da solución

Multiplica 4! e 4! para obter \left(4!\right)^{2}.

$$\left(\frac{1}{3}\right)^{8}+8\times \frac{2}{3}\times \left(\frac{1}{3}\right)^{7}+\frac{8!}{6!\times 2!}\times \left(\frac{2}{3}\right)^{2}\times \left(\frac{1}{3}\right)^{6}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Calcula \frac{1}{3} á potencia de 8 e obtén \frac{1}{6561}.

$$\frac{1}{6561}+8\times \frac{2}{3}\times \left(\frac{1}{3}\right)^{7}+\frac{8!}{6!\times 2!}\times \left(\frac{2}{3}\right)^{2}\times \left(\frac{1}{3}\right)^{6}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Expresa 8\times \frac{2}{3} como unha única fracción.

$$\frac{1}{6561}+\frac{8\times 2}{3}\times \left(\frac{1}{3}\right)^{7}+\frac{8!}{6!\times 2!}\times \left(\frac{2}{3}\right)^{2}\times \left(\frac{1}{3}\right)^{6}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Multiplica 8 e 2 para obter 16.

$$\frac{1}{6561}+\frac{16}{3}\times \left(\frac{1}{3}\right)^{7}+\frac{8!}{6!\times 2!}\times \left(\frac{2}{3}\right)^{2}\times \left(\frac{1}{3}\right)^{6}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Calcula \frac{1}{3} á potencia de 7 e obtén \frac{1}{2187}.

$$\frac{1}{6561}+\frac{16}{3}\times \frac{1}{2187}+\frac{8!}{6!\times 2!}\times \left(\frac{2}{3}\right)^{2}\times \left(\frac{1}{3}\right)^{6}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Multiplica \frac{16}{3} por \frac{1}{2187} mediante a multiplicación do numerador polo numerador e do denominador polo denominador.

$$\frac{1}{6561}+\frac{16\times 1}{3\times 2187}+\frac{8!}{6!\times 2!}\times \left(\frac{2}{3}\right)^{2}\times \left(\frac{1}{3}\right)^{6}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Fai as multiplicacións na fracción \frac{16\times 1}{3\times 2187}.

$$\frac{1}{6561}+\frac{16}{6561}+\frac{8!}{6!\times 2!}\times \left(\frac{2}{3}\right)^{2}\times \left(\frac{1}{3}\right)^{6}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Dado que \frac{1}{6561} e \frac{16}{6561} teñen o mesmo denominador, súmaos mediante a suma dos seus numeradores.

$$\frac{1+16}{6561}+\frac{8!}{6!\times 2!}\times \left(\frac{2}{3}\right)^{2}\times \left(\frac{1}{3}\right)^{6}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Suma 1 e 16 para obter 17.

$$\frac{17}{6561}+\frac{8!}{6!\times 2!}\times \left(\frac{2}{3}\right)^{2}\times \left(\frac{1}{3}\right)^{6}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

O factor de 8 é 40320.

$$\frac{17}{6561}+\frac{40320}{6!\times 2!}\times \left(\frac{2}{3}\right)^{2}\times \left(\frac{1}{3}\right)^{6}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

O factor de 6 é 720.

$$\frac{17}{6561}+\frac{40320}{720\times 2!}\times \left(\frac{2}{3}\right)^{2}\times \left(\frac{1}{3}\right)^{6}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

O factor de 2 é 2.

$$\frac{17}{6561}+\frac{40320}{720\times 2}\times \left(\frac{2}{3}\right)^{2}\times \left(\frac{1}{3}\right)^{6}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Multiplica 720 e 2 para obter 1440.

$$\frac{17}{6561}+\frac{40320}{1440}\times \left(\frac{2}{3}\right)^{2}\times \left(\frac{1}{3}\right)^{6}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Divide 40320 entre 1440 para obter 28.

$$\frac{17}{6561}+28\times \left(\frac{2}{3}\right)^{2}\times \left(\frac{1}{3}\right)^{6}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Calcula \frac{2}{3} á potencia de 2 e obtén \frac{4}{9}.

$$\frac{17}{6561}+28\times \frac{4}{9}\times \left(\frac{1}{3}\right)^{6}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Expresa 28\times \frac{4}{9} como unha única fracción.

$$\frac{17}{6561}+\frac{28\times 4}{9}\times \left(\frac{1}{3}\right)^{6}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Multiplica 28 e 4 para obter 112.

$$\frac{17}{6561}+\frac{112}{9}\times \left(\frac{1}{3}\right)^{6}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Calcula \frac{1}{3} á potencia de 6 e obtén \frac{1}{729}.

$$\frac{17}{6561}+\frac{112}{9}\times \frac{1}{729}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Multiplica \frac{112}{9} por \frac{1}{729} mediante a multiplicación do numerador polo numerador e do denominador polo denominador.

$$\frac{17}{6561}+\frac{112\times 1}{9\times 729}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Fai as multiplicacións na fracción \frac{112\times 1}{9\times 729}.

$$\frac{17}{6561}+\frac{112}{6561}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Dado que \frac{17}{6561} e \frac{112}{6561} teñen o mesmo denominador, súmaos mediante a suma dos seus numeradores.

$$\frac{17+112}{6561}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Suma 17 e 112 para obter 129.

$$\frac{129}{6561}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Reduce a fracción \frac{129}{6561} a termos máis baixos extraendo e cancelando 3.

$$\frac{43}{2187}+\frac{8!}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

O factor de 8 é 40320.

$$\frac{43}{2187}+\frac{40320}{5!\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

O factor de 5 é 120.

$$\frac{43}{2187}+\frac{40320}{120\times 3!}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

O factor de 3 é 6.

$$\frac{43}{2187}+\frac{40320}{120\times 6}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Multiplica 120 e 6 para obter 720.

$$\frac{43}{2187}+\frac{40320}{720}\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Divide 40320 entre 720 para obter 56.

$$\frac{43}{2187}+56\times \left(\frac{2}{3}\right)^{3}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Calcula \frac{2}{3} á potencia de 3 e obtén \frac{8}{27}.

$$\frac{43}{2187}+56\times \frac{8}{27}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Expresa 56\times \frac{8}{27} como unha única fracción.

$$\frac{43}{2187}+\frac{56\times 8}{27}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Multiplica 56 e 8 para obter 448.

$$\frac{43}{2187}+\frac{448}{27}\times \left(\frac{1}{3}\right)^{5}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Calcula \frac{1}{3} á potencia de 5 e obtén \frac{1}{243}.

$$\frac{43}{2187}+\frac{448}{27}\times \frac{1}{243}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Multiplica \frac{448}{27} por \frac{1}{243} mediante a multiplicación do numerador polo numerador e do denominador polo denominador.

$$\frac{43}{2187}+\frac{448\times 1}{27\times 243}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Fai as multiplicacións na fracción \frac{448\times 1}{27\times 243}.

$$\frac{43}{2187}+\frac{448}{6561}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

O mínimo común múltiplo de 2187 e 6561 é 6561. Converte \frac{43}{2187} e \frac{448}{6561} a fraccións co denominador 6561.

$$\frac{129}{6561}+\frac{448}{6561}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Dado que \frac{129}{6561} e \frac{448}{6561} teñen o mesmo denominador, súmaos mediante a suma dos seus numeradores.

$$\frac{129+448}{6561}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Suma 129 e 448 para obter 577.

$$\frac{577}{6561}+\frac{8!}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

O factor de 8 é 40320.

$$\frac{577}{6561}+\frac{40320}{\left(4!\right)^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

O factor de 4 é 24.

$$\frac{577}{6561}+\frac{40320}{24^{2}}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Calcula 24 á potencia de 2 e obtén 576.

$$\frac{577}{6561}+\frac{40320}{576}\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Divide 40320 entre 576 para obter 70.

$$\frac{577}{6561}+70\times \left(\frac{2}{3}\right)^{4}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Calcula \frac{2}{3} á potencia de 4 e obtén \frac{16}{81}.

$$\frac{577}{6561}+70\times \frac{16}{81}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Expresa 70\times \frac{16}{81} como unha única fracción.

$$\frac{577}{6561}+\frac{70\times 16}{81}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Multiplica 70 e 16 para obter 1120.

$$\frac{577}{6561}+\frac{1120}{81}\times \left(\frac{1}{3}\right)^{4}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Calcula \frac{1}{3} á potencia de 4 e obtén \frac{1}{81}.

$$\frac{577}{6561}+\frac{1120}{81}\times \frac{1}{81}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Multiplica \frac{1120}{81} por \frac{1}{81} mediante a multiplicación do numerador polo numerador e do denominador polo denominador.

$$\frac{577}{6561}+\frac{1120\times 1}{81\times 81}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Fai as multiplicacións na fracción \frac{1120\times 1}{81\times 81}.

$$\frac{577}{6561}+\frac{1120}{6561}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Dado que \frac{577}{6561} e \frac{1120}{6561} teñen o mesmo denominador, súmaos mediante a suma dos seus numeradores.

$$\frac{577+1120}{6561}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Suma 577 e 1120 para obter 1697.

$$\frac{1697}{6561}+\frac{8!}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

O factor de 8 é 40320.

$$\frac{1697}{6561}+\frac{40320}{3!\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

O factor de 3 é 6.

$$\frac{1697}{6561}+\frac{40320}{6\times 5!}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

O factor de 5 é 120.

$$\frac{1697}{6561}+\frac{40320}{6\times 120}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Multiplica 6 e 120 para obter 720.

$$\frac{1697}{6561}+\frac{40320}{720}\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Divide 40320 entre 720 para obter 56.

$$\frac{1697}{6561}+56\times \left(\frac{2}{3}\right)^{5}\times \left(\frac{1}{3}\right)^{3}$$

Calcula \frac{2}{3} á potencia de 5 e obtén \frac{32}{243}.

$$\frac{1697}{6561}+56\times \frac{32}{243}\times \left(\frac{1}{3}\right)^{3}$$

Expresa 56\times \frac{32}{243} como unha única fracción.

$$\frac{1697}{6561}+\frac{56\times 32}{243}\times \left(\frac{1}{3}\right)^{3}$$

Multiplica 56 e 32 para obter 1792.

$$\frac{1697}{6561}+\frac{1792}{243}\times \left(\frac{1}{3}\right)^{3}$$

Calcula \frac{1}{3} á potencia de 3 e obtén \frac{1}{27}.

$$\frac{1697}{6561}+\frac{1792}{243}\times \frac{1}{27}$$

Multiplica \frac{1792}{243} por \frac{1}{27} mediante a multiplicación do numerador polo numerador e do denominador polo denominador.

$$\frac{1697}{6561}+\frac{1792\times 1}{243\times 27}$$

Fai as multiplicacións na fracción \frac{1792\times 1}{243\times 27}.

$$\frac{1697}{6561}+\frac{1792}{6561}$$

Dado que \frac{1697}{6561} e \frac{1792}{6561} teñen o mesmo denominador, súmaos mediante a suma dos seus numeradores.

$$\frac{1697+1792}{6561}$$

Suma 1697 e 1792 para obter 3489.

$$\frac{3489}{6561}$$

Reduce a fracción \frac{3489}{6561} a termos máis baixos extraendo e cancelando 3.

$$\frac{1163}{2187}$$

Factorizar

$$\frac{1163}{3 ^ {7}} = 0.5317786922725194$$