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\left(\frac{\left(\frac{7}{4}-\frac{1}{2}\right)^{2}}{\left(1-\left(\frac{5}{4}-\frac{1}{2}\right)\right)^{2}}\times \frac{\frac{2}{5}}{\frac{5}{4}}\times \frac{1}{14}\right)^{2}
Suma 1 e \frac{3}{4} para obter \frac{7}{4}.
\left(\frac{\left(\frac{5}{4}\right)^{2}}{\left(1-\left(\frac{5}{4}-\frac{1}{2}\right)\right)^{2}}\times \frac{\frac{2}{5}}{\frac{5}{4}}\times \frac{1}{14}\right)^{2}
Resta \frac{1}{2} de \frac{7}{4} para obter \frac{5}{4}.
\left(\frac{\frac{25}{16}}{\left(1-\left(\frac{5}{4}-\frac{1}{2}\right)\right)^{2}}\times \frac{\frac{2}{5}}{\frac{5}{4}}\times \frac{1}{14}\right)^{2}
Calcula \frac{5}{4} á potencia de 2 e obtén \frac{25}{16}.
\left(\frac{\frac{25}{16}}{\left(1-\frac{3}{4}\right)^{2}}\times \frac{\frac{2}{5}}{\frac{5}{4}}\times \frac{1}{14}\right)^{2}
Resta \frac{1}{2} de \frac{5}{4} para obter \frac{3}{4}.
\left(\frac{\frac{25}{16}}{\left(\frac{1}{4}\right)^{2}}\times \frac{\frac{2}{5}}{\frac{5}{4}}\times \frac{1}{14}\right)^{2}
Resta \frac{3}{4} de 1 para obter \frac{1}{4}.
\left(\frac{\frac{25}{16}}{\frac{1}{16}}\times \frac{\frac{2}{5}}{\frac{5}{4}}\times \frac{1}{14}\right)^{2}
Calcula \frac{1}{4} á potencia de 2 e obtén \frac{1}{16}.
\left(\frac{25}{16}\times 16\times \frac{\frac{2}{5}}{\frac{5}{4}}\times \frac{1}{14}\right)^{2}
Divide \frac{25}{16} entre \frac{1}{16} mediante a multiplicación de \frac{25}{16} polo recíproco de \frac{1}{16}.
\left(25\times \frac{\frac{2}{5}}{\frac{5}{4}}\times \frac{1}{14}\right)^{2}
Multiplica \frac{25}{16} e 16 para obter 25.
\left(25\times \frac{2}{5}\times \frac{4}{5}\times \frac{1}{14}\right)^{2}
Divide \frac{2}{5} entre \frac{5}{4} mediante a multiplicación de \frac{2}{5} polo recíproco de \frac{5}{4}.
\left(25\times \frac{8}{25}\times \frac{1}{14}\right)^{2}
Multiplica \frac{2}{5} e \frac{4}{5} para obter \frac{8}{25}.
\left(8\times \frac{1}{14}\right)^{2}
Multiplica 25 e \frac{8}{25} para obter 8.
\left(\frac{4}{7}\right)^{2}
Multiplica 8 e \frac{1}{14} para obter \frac{4}{7}.
\frac{16}{49}
Calcula \frac{4}{7} á potencia de 2 e obtén \frac{16}{49}.