Réitigh 836/18+θ*x=3sqrt{x^2}

$$8 \frac{ 36 }{ 18 } + \theta \times x=3 \sqrt{ { x }^{ 2 } }$$

Réitigh do θ. (complex solution)

$$\theta =-\frac{-3\sqrt{x^{2}}+10}{x}$$

$$x\neq 0$$

Céimeanna chun Cothromóidí Líneacha a Réiteach

Méadaigh an dá thaobh den chothromóid faoi 18.

$$8\times 18+36+18\theta x=54\sqrt{x^{2}}$$

Méadaigh 8 agus 18 chun 144 a fháil.

$$144+36+18\theta x=54\sqrt{x^{2}}$$

Suimigh 144 agus 36 chun 180 a fháil.

$$180+18\theta x=54\sqrt{x^{2}}$$

Bain 180 ón dá thaobh.

$$18\theta x=54\sqrt{x^{2}}-180$$

Tá an chothromóid i bhfoirm chaighdeánach.

$$18x\theta =54\sqrt{x^{2}}-180$$

Roinn an dá thaobh faoi 18x.

$$\frac{18x\theta }{18x}=\frac{54\sqrt{x^{2}}-180}{18x}$$

Má roinntear é faoi 18x cuirtear an iolrúchán faoi 18x ar ceal.

$$\theta =\frac{54\sqrt{x^{2}}-180}{18x}$$

Roinn 54\sqrt{x^{2}}-180 faoi 18x.

$$\theta =\frac{3\sqrt{x^{2}}-10}{x}$$

Réitigh do θ.

$$\theta =-\frac{-3|x|+10}{x}$$

$$x\neq 0$$

Céimeanna chun Cothromóidí Líneacha a Réiteach

Méadaigh an dá thaobh den chothromóid faoi 18.

$$8\times 18+36+18\theta x=54\sqrt{x^{2}}$$

Méadaigh 8 agus 18 chun 144 a fháil.

$$144+36+18\theta x=54\sqrt{x^{2}}$$

Suimigh 144 agus 36 chun 180 a fháil.

$$180+18\theta x=54\sqrt{x^{2}}$$

Bain 180 ón dá thaobh.

$$18\theta x=54\sqrt{x^{2}}-180$$

Tá an chothromóid i bhfoirm chaighdeánach.

$$18x\theta =54\sqrt{x^{2}}-180$$

Roinn an dá thaobh faoi 18x.

$$\frac{18x\theta }{18x}=\frac{54|x|-180}{18x}$$

Má roinntear é faoi 18x cuirtear an iolrúchán faoi 18x ar ceal.

$$\theta =\frac{54|x|-180}{18x}$$

Roinn 54|x|-180 faoi 18x.

$$\theta =\frac{3|x|-10}{x}$$

Réitigh do x. (complex solution)

$$\left\{\begin{matrix}x=\frac{10}{3-\theta }\text{, }&\theta \neq 3\text{ and }arg(\frac{x\theta +10}{3})<\pi \\x=-\frac{10}{\theta +3}\text{, }&\theta \neq -3\text{ and }arg(\frac{x\theta +10}{3})<\pi \end{matrix}\right.$$

Réitigh do x.

$$\left\{\begin{matrix}x=-\frac{10}{\theta -3}\text{, }&\theta <3\\x=-\frac{10}{\theta +3}\text{, }&\theta >-3\end{matrix}\right.$$