Réitigh 550=22/75x5x7x

$$550 = \frac{ 22 }{ 7 } 5x5x7x$$

Réitigh do x.

$$x=\frac{35}{x_{5}x_{7}}$$

$$x_{7}\neq 0\text{ and }x_{5}\neq 0$$

Céimeanna chun Cothromóidí Líneacha a Réiteach

Méadaigh \frac{22}{7} agus 5 chun \frac{110}{7} a fháil.

$$550=\frac{110}{7}x_{5}x_{7}x$$

Athraigh na taobhanna ionas go mbeidh na téarmaí inathraitheacha ar fad ar an taobh clé.

$$\frac{110}{7}x_{5}x_{7}x=550$$

Tá an chothromóid i bhfoirm chaighdeánach.

$$\frac{110x_{5}x_{7}}{7}x=550$$

Roinn an dá thaobh faoi \frac{110}{7}x_{5}x_{7}.

$$\frac{7\times \frac{110x_{5}x_{7}}{7}x}{110x_{5}x_{7}}=\frac{7\times 550}{110x_{5}x_{7}}$$

Má roinntear é faoi \frac{110}{7}x_{5}x_{7} cuirtear an iolrúchán faoi \frac{110}{7}x_{5}x_{7} ar ceal.

$$x=\frac{7\times 550}{110x_{5}x_{7}}$$

Roinn 550 faoi \frac{110}{7}x_{5}x_{7}.

$$x=\frac{35}{x_{5}x_{7}}$$

Réitigh do x_5.

$$x_{5}=\frac{35}{xx_{7}}$$

$$x\neq 0\text{ and }x_{7}\neq 0$$

Céimeanna chun Cothromóidí Líneacha a Réiteach

Méadaigh \frac{22}{7} agus 5 chun \frac{110}{7} a fháil.

$$550=\frac{110}{7}x_{5}x_{7}x$$

Athraigh na taobhanna ionas go mbeidh na téarmaí inathraitheacha ar fad ar an taobh clé.

$$\frac{110}{7}x_{5}x_{7}x=550$$

Tá an chothromóid i bhfoirm chaighdeánach.

$$\frac{110xx_{7}}{7}x_{5}=550$$

Roinn an dá thaobh faoi \frac{110}{7}x_{7}x.

$$\frac{7\times \frac{110xx_{7}}{7}x_{5}}{110xx_{7}}=\frac{7\times 550}{110xx_{7}}$$

Má roinntear é faoi \frac{110}{7}x_{7}x cuirtear an iolrúchán faoi \frac{110}{7}x_{7}x ar ceal.

$$x_{5}=\frac{7\times 550}{110xx_{7}}$$

Roinn 550 faoi \frac{110}{7}x_{7}x.

$$x_{5}=\frac{35}{xx_{7}}$$