Réitigh 45left(1+xright)^2=9

$$45 { \left(1+x \right) }^{ 2 } =9$$

Réitigh do x.

$$x=\frac{\sqrt{5}}{5}-1\approx -0.552786405$$

$$x=-\frac{\sqrt{5}}{5}-1\approx -1.447213595$$

Céimeanna tríd an bhFréamh Chearnach a Fháil

Roinn an dá thaobh faoi 45.

$$\frac{45\left(x+1\right)^{2}}{45}=\frac{9}{45}$$

Má roinntear é faoi 45 cuirtear an iolrúchán faoi 45 ar ceal.

$$\left(x+1\right)^{2}=\frac{9}{45}$$

Laghdaigh an codán \frac{9}{45} chuig na téarmaí is ísle trí 9 a bhaint agus a chealú.

$$\left(x+1\right)^{2}=\frac{1}{5}$$

Tóg fréamh chearnach an dá thaobh den chothromóid.

$$x+1=\frac{\sqrt{5}}{5} x+1=-\frac{\sqrt{5}}{5}$$

Bain 1 ón dá thaobh den chothromóid.

$$x+1-1=\frac{\sqrt{5}}{5}-1 x+1-1=-\frac{\sqrt{5}}{5}-1$$

Má dhealaítear 1 uaidh féin faightear 0.

$$x=\frac{\sqrt{5}}{5}-1 x=-\frac{\sqrt{5}}{5}-1$$