Réitigh 2x^2*1/x^2+3x-10

$$2 x ^ { 2 } \cdot \frac { 1 } { x ^ { 2 } + 3 x - 10 }$$

Luacháil

$$\frac{2x^{2}}{\left(x-2\right)\left(x+5\right)}$$

Céimeanna Réitigh

Scríobh 2\times \frac{1}{x^{2}+3x-10} mar chodán aonair.

$$\frac{2}{x^{2}+3x-10}x^{2}$$

Scríobh \frac{2}{x^{2}+3x-10}x^{2} mar chodán aonair.

$$\frac{2x^{2}}{x^{2}+3x-10}$$

Difreálaigh w.r.t. x

$$\frac{2x\left(3x-20\right)}{\left(\left(x-2\right)\left(x+5\right)\right)^{2}}$$

Céimeanna ag Baint Úsáid as Riail na nDíorthach don Líon

Scríobh 2\times \frac{1}{x^{2}+3x-10} mar chodán aonair.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{2}{x^{2}+3x-10}x^{2})$$

Scríobh \frac{2}{x^{2}+3x-10}x^{2} mar chodán aonair.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{2x^{2}}{x^{2}+3x-10})$$

Do dhá fheidhm indifreáilte ar bith, is ionann díorthach líon an dá fheidhme agus an t-ainmneoir méadaithe faoi dhíorthach an uimhreora lúide an t-uimhreoir méadaithe faoi dhíorthach an ainmneora, agus iad ar fad roinnte faoin ainmneoir cearnaithe.

$$\frac{\left(x^{2}+3x^{1}-10\right)\frac{\mathrm{d}}{\mathrm{d}x}(2x^{2})-2x^{2}\frac{\mathrm{d}}{\mathrm{d}x}(x^{2}+3x^{1}-10)}{\left(x^{2}+3x^{1}-10\right)^{2}}$$

Is ionann díorthach iltéarmaigh agus suim dhíorthaigh a théarmaí. Is ionann díorthach téarma thairisigh agus 0. Is ionann díorthach ax^{n} agus nax^{n-1}.

$$\frac{\left(x^{2}+3x^{1}-10\right)\times 2\times 2x^{2-1}-2x^{2}\left(2x^{2-1}+3x^{1-1}\right)}{\left(x^{2}+3x^{1}-10\right)^{2}}$$

Simpligh.

$$\frac{\left(x^{2}+3x^{1}-10\right)\times 4x^{1}-2x^{2}\left(2x^{1}+3x^{0}\right)}{\left(x^{2}+3x^{1}-10\right)^{2}}$$

Méadaigh x^{2}+3x^{1}-10 faoi 4x^{1}.

$$\frac{x^{2}\times 4x^{1}+3x^{1}\times 4x^{1}-10\times 4x^{1}-2x^{2}\left(2x^{1}+3x^{0}\right)}{\left(x^{2}+3x^{1}-10\right)^{2}}$$

Méadaigh 2x^{2} faoi 2x^{1}+3x^{0}.

$$\frac{x^{2}\times 4x^{1}+3x^{1}\times 4x^{1}-10\times 4x^{1}-\left(2x^{2}\times 2x^{1}+2x^{2}\times 3x^{0}\right)}{\left(x^{2}+3x^{1}-10\right)^{2}}$$

Chun cumhachtaí an bhoinn chéanna a mhéadú, suimigh a n-easpónaint.

$$\frac{4x^{2+1}+3\times 4x^{1+1}-10\times 4x^{1}-\left(2\times 2x^{2+1}+2\times 3x^{2}\right)}{\left(x^{2}+3x^{1}-10\right)^{2}}$$

Simpligh.

$$\frac{4x^{3}+12x^{2}-40x^{1}-\left(4x^{3}+6x^{2}\right)}{\left(x^{2}+3x^{1}-10\right)^{2}}$$

Cuir téarmaí cosúla le chéile.

$$\frac{6x^{2}-40x^{1}}{\left(x^{2}+3x^{1}-10\right)^{2}}$$

Do théarma ar bith t, t^{1}=t.

$$\frac{6x^{2}-40x}{\left(x^{2}+3x-10\right)^{2}}$$