Réitigh 2sqrt{4(t-1)}=sqrt{4(2t-1)}

$$2 \sqrt { 4 ( t - 1 ) } = \sqrt { 4 ( 2 t - 1 ) }$$

Réitigh do t.

$$t = \frac{3}{2} = 1\frac{1}{2} = 1.5$$

Céimeanna Réitigh

Cearnaigh an dá thaobh den chothromóid.

$$\left(2\sqrt{4\left(t-1\right)}\right)^{2}=\left(\sqrt{4\left(2t-1\right)}\right)^{2}$$

Úsáid an t-airí dáileach chun 4 a mhéadú faoi t-1.

$$\left(2\sqrt{4t-4}\right)^{2}=\left(\sqrt{4\left(2t-1\right)}\right)^{2}$$

Fairsingigh \left(2\sqrt{4t-4}\right)^{2}

$$2^{2}\left(\sqrt{4t-4}\right)^{2}=\left(\sqrt{4\left(2t-1\right)}\right)^{2}$$

Ríomh cumhacht 2 de 2 agus faigh 4.

$$4\left(\sqrt{4t-4}\right)^{2}=\left(\sqrt{4\left(2t-1\right)}\right)^{2}$$

Ríomh cumhacht \sqrt{4t-4} de 2 agus faigh 4t-4.

$$4\left(4t-4\right)=\left(\sqrt{4\left(2t-1\right)}\right)^{2}$$

Úsáid an t-airí dáileach chun 4 a mhéadú faoi 4t-4.

$$16t-16=\left(\sqrt{4\left(2t-1\right)}\right)^{2}$$

Úsáid an t-airí dáileach chun 4 a mhéadú faoi 2t-1.

$$16t-16=\left(\sqrt{8t-4}\right)^{2}$$

Ríomh cumhacht \sqrt{8t-4} de 2 agus faigh 8t-4.

$$16t-16=8t-4$$

Bain 8t ón dá thaobh.

$$16t-16-8t=-4$$

Comhcheangail 16t agus -8t chun 8t a fháil.

$$8t-16=-4$$

Cuir 16 leis an dá thaobh.

$$8t=-4+16$$

Suimigh -4 agus 16 chun 12 a fháil.

$$8t=12$$

Roinn an dá thaobh faoi 8.

$$t=\frac{12}{8}$$

Laghdaigh an codán \frac{12}{8} chuig na téarmaí is ísle trí 4 a bhaint agus a chealú.

$$t=\frac{3}{2}$$

Cuir \frac{3}{2} in ionad t sa chothromóid 2\sqrt{4\left(t-1\right)}=\sqrt{4\left(2t-1\right)}.

$$2\sqrt{4\left(\frac{3}{2}-1\right)}=\sqrt{4\left(2\times \frac{3}{2}-1\right)}$$

Simpligh. An luach t=\frac{3}{2} shásaíonn an gcothromóid.

$$2\times 2^{\frac{1}{2}}=2\times 2^{\frac{1}{2}}$$

Ag an chothromóid 2\sqrt{4\left(t-1\right)}=\sqrt{4\left(2t-1\right)} réiteach uathúil.

$$t=\frac{3}{2}$$