Réitigh (x-y)(400+5y)=4250

$$( x - y ) ( 400 + 5 y ) = 4250$$

Réitigh do x.

$$x=\frac{y^{2}+80y+850}{y+80}$$

$$y\neq -80$$

Céimeanna chun Cothromóidí Líneacha a Réiteach

Úsáid an t-airí dáileach chun x-y a mhéadú faoi 400+5y.

$$400x+5xy-400y-5y^{2}=4250$$

Cuir 400y leis an dá thaobh.

$$400x+5xy-5y^{2}=4250+400y$$

Cuir 5y^{2} leis an dá thaobh.

$$400x+5xy=4250+400y+5y^{2}$$

Comhcheangail na téarmaí ar fad ina bhfuil x.

$$\left(400+5y\right)x=4250+400y+5y^{2}$$

Tá an chothromóid i bhfoirm chaighdeánach.

$$\left(5y+400\right)x=5y^{2}+400y+4250$$

Roinn an dá thaobh faoi 400+5y.

$$\frac{\left(5y+400\right)x}{5y+400}=\frac{5y^{2}+400y+4250}{5y+400}$$

Má roinntear é faoi 400+5y cuirtear an iolrúchán faoi 400+5y ar ceal.

$$x=\frac{5y^{2}+400y+4250}{5y+400}$$

Roinn 4250+400y+5y^{2} faoi 400+5y.

$$x=\frac{y^{2}+80y+850}{y+80}$$

Réitigh do y. (complex solution)

$$y=\frac{-\sqrt{x^{2}+160x+3000}+x-80}{2}$$

$$y=\frac{\sqrt{x^{2}+160x+3000}+x-80}{2}$$

Réitigh do y.

$$y=\frac{-\sqrt{x^{2}+160x+3000}+x-80}{2}$$

$$y=\frac{\sqrt{x^{2}+160x+3000}+x-80}{2}\text{, }x\geq 10\sqrt{34}-80\text{ or }x\leq -10\sqrt{34}-80$$