Réitigh ∫ sqrt[3]{3t}dt=(3t)^4/2/4tc

$$\int \sqrt[ 3 ] { 3 t } d t = \frac { ( 3 t ) ^ { 4 / 2 } } { 4 } t c$$

Réitigh do c.

$$\left\{\begin{matrix}c=\frac{3^{\frac{4}{3}}}{9t^{\frac{5}{3}}}+\frac{4С}{9t^{3}}\text{, }&t\neq 0\\c\in \mathrm{R}\text{, }&С=0\text{ and }t=0\end{matrix}\right.$$

Céimeanna chun Cothromóidí Líneacha a Réiteach

Méadaigh an dá thaobh den chothromóid faoi 4.

$$4\int \sqrt[3]{3t}\mathrm{d}t=\left(3t\right)^{\frac{4}{2}}tc$$

Roinn 4 faoi 2 chun 2 a fháil.

$$4\int \sqrt[3]{3t}\mathrm{d}t=\left(3t\right)^{2}tc$$

Fairsingigh \left(3t\right)^{2}

$$4\int \sqrt[3]{3t}\mathrm{d}t=3^{2}t^{2}tc$$

Ríomh cumhacht 3 de 2 agus faigh 9.

$$4\int \sqrt[3]{3t}\mathrm{d}t=9t^{2}tc$$

Chun cumhachtaí den bhonn céanna a iolrú, suimigh a n-easpónaint. Suimigh 2 agus 1 chun 3 a bhaint amach.

$$4\int \sqrt[3]{3t}\mathrm{d}t=9t^{3}c$$

Athraigh na taobhanna ionas go mbeidh na téarmaí inathraitheacha ar fad ar an taobh clé.

$$9t^{3}c=4\int \sqrt[3]{3t}\mathrm{d}t$$

Tá an chothromóid i bhfoirm chaighdeánach.

$$9t^{3}c=4\sqrt[3]{3}t^{\frac{4}{3}}+4С$$

Roinn an dá thaobh faoi 9t^{3}.

$$\frac{9t^{3}c}{9t^{3}}=\frac{\frac{4\times \left(3t\right)^{\frac{4}{3}}}{3}+4С}{9t^{3}}$$

Má roinntear é faoi 9t^{3} cuirtear an iolrúchán faoi 9t^{3} ar ceal.

$$c=\frac{\frac{4\times \left(3t\right)^{\frac{4}{3}}}{3}+4С}{9t^{3}}$$

Roinn \frac{4\times \left(3t\right)^{\frac{4}{3}}}{3}+4С faoi 9t^{3}.

$$c=\frac{4\left(\frac{\left(3t\right)^{\frac{4}{3}}}{3}+С\right)}{9t^{3}}$$