Lutasin ang 2a^3+6a^2+1/2a+3/2

$$2 a ^ { 3 } + 6 a ^ { 2 } + \frac { 1 } { 2 } a + \frac { 3 } { 2 }$$

I-factor

$$\frac{\left(a+3\right)\left(4a^{2}+1\right)}{2}$$

Mga Hakbang ng Solution

I-factor out ang \frac{1}{2}.

$$\frac{4a^{3}+12a^{2}+a+3}{2}$$

Isaalang-alang ang 4a^{3}+12a^{2}+a+3. Gawin ang grouping na 4a^{3}+12a^{2}+a+3=\left(4a^{3}+12a^{2}\right)+\left(a+3\right), at i-factor out ang 4a^{2} sa 4a^{3}+12a^{2}.

$$4a^{2}\left(a+3\right)+a+3$$

I-factor out ang common term na a+3 gamit ang distributive property.

$$\left(a+3\right)\left(4a^{2}+1\right)$$

I-rewrite ang kumpletong naka-factor na expression. Ang polynomial 4a^{2}+1 ay hindi naka-factor dahil wala itong anumang rational root.

$$\frac{\left(a+3\right)\left(4a^{2}+1\right)}{2}$$

I-evaluate

$$\frac{\left(a+3\right)\left(4a^{2}+1\right)}{2}$$