Lutasin ang frac{31sqrt{2}+31sqrt{5}}{2sqrt{10}-3}-frac{62sqrt{2}}{3-2sqrt{10}}

$$\frac { 31 \sqrt { 2 } + 31 \sqrt { 5 } } { 2 \sqrt { 10 } - 3 } - \frac { 62 \sqrt { 2 } } { 3 - 2 \sqrt { 10 } }$$

I-evaluate

$$15\sqrt{5}+19\sqrt{2}\approx 60.411077348$$

Mga Hakbang ng Solution

I-rationalize ang denominator ng \frac{31\sqrt{2}+31\sqrt{5}}{2\sqrt{10}-3} sa pamamagitan ng pag-multiply ng numerator at denominator sa 2\sqrt{10}+3.

$$\frac{\left(31\sqrt{2}+31\sqrt{5}\right)\left(2\sqrt{10}+3\right)}{\left(2\sqrt{10}-3\right)\left(2\sqrt{10}+3\right)}-\frac{62\sqrt{2}}{3-2\sqrt{10}}$$

Isaalang-alang ang \left(2\sqrt{10}-3\right)\left(2\sqrt{10}+3\right). Maaaring ma-transform ang pag-multiply sa difference ng mga square gamit ang rule na: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$\frac{\left(31\sqrt{2}+31\sqrt{5}\right)\left(2\sqrt{10}+3\right)}{\left(2\sqrt{10}\right)^{2}-3^{2}}-\frac{62\sqrt{2}}{3-2\sqrt{10}}$$

Palawakin ang \left(2\sqrt{10}\right)^{2}.

$$\frac{\left(31\sqrt{2}+31\sqrt{5}\right)\left(2\sqrt{10}+3\right)}{2^{2}\left(\sqrt{10}\right)^{2}-3^{2}}-\frac{62\sqrt{2}}{3-2\sqrt{10}}$$

Kalkulahin ang 2 sa power ng 2 at kunin ang 4.

$$\frac{\left(31\sqrt{2}+31\sqrt{5}\right)\left(2\sqrt{10}+3\right)}{4\left(\sqrt{10}\right)^{2}-3^{2}}-\frac{62\sqrt{2}}{3-2\sqrt{10}}$$

Ang square ng \sqrt{10} ay 10.

$$\frac{\left(31\sqrt{2}+31\sqrt{5}\right)\left(2\sqrt{10}+3\right)}{4\times 10-3^{2}}-\frac{62\sqrt{2}}{3-2\sqrt{10}}$$

I-multiply ang 4 at 10 para makuha ang 40.

$$\frac{\left(31\sqrt{2}+31\sqrt{5}\right)\left(2\sqrt{10}+3\right)}{40-3^{2}}-\frac{62\sqrt{2}}{3-2\sqrt{10}}$$

Kalkulahin ang 3 sa power ng 2 at kunin ang 9.

$$\frac{\left(31\sqrt{2}+31\sqrt{5}\right)\left(2\sqrt{10}+3\right)}{40-9}-\frac{62\sqrt{2}}{3-2\sqrt{10}}$$

I-subtract ang 9 mula sa 40 para makuha ang 31.

$$\frac{\left(31\sqrt{2}+31\sqrt{5}\right)\left(2\sqrt{10}+3\right)}{31}-\frac{62\sqrt{2}}{3-2\sqrt{10}}$$

I-rationalize ang denominator ng \frac{62\sqrt{2}}{3-2\sqrt{10}} sa pamamagitan ng pag-multiply ng numerator at denominator sa 3+2\sqrt{10}.

$$\frac{\left(31\sqrt{2}+31\sqrt{5}\right)\left(2\sqrt{10}+3\right)}{31}-\frac{62\sqrt{2}\left(3+2\sqrt{10}\right)}{\left(3-2\sqrt{10}\right)\left(3+2\sqrt{10}\right)}$$

Isaalang-alang ang \left(3-2\sqrt{10}\right)\left(3+2\sqrt{10}\right). Maaaring ma-transform ang pag-multiply sa difference ng mga square gamit ang rule na: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$\frac{\left(31\sqrt{2}+31\sqrt{5}\right)\left(2\sqrt{10}+3\right)}{31}-\frac{62\sqrt{2}\left(3+2\sqrt{10}\right)}{3^{2}-\left(-2\sqrt{10}\right)^{2}}$$

Kalkulahin ang 3 sa power ng 2 at kunin ang 9.

$$\frac{\left(31\sqrt{2}+31\sqrt{5}\right)\left(2\sqrt{10}+3\right)}{31}-\frac{62\sqrt{2}\left(3+2\sqrt{10}\right)}{9-\left(-2\sqrt{10}\right)^{2}}$$

Palawakin ang \left(-2\sqrt{10}\right)^{2}.

$$\frac{\left(31\sqrt{2}+31\sqrt{5}\right)\left(2\sqrt{10}+3\right)}{31}-\frac{62\sqrt{2}\left(3+2\sqrt{10}\right)}{9-\left(-2\right)^{2}\left(\sqrt{10}\right)^{2}}$$

Kalkulahin ang -2 sa power ng 2 at kunin ang 4.

$$\frac{\left(31\sqrt{2}+31\sqrt{5}\right)\left(2\sqrt{10}+3\right)}{31}-\frac{62\sqrt{2}\left(3+2\sqrt{10}\right)}{9-4\left(\sqrt{10}\right)^{2}}$$

Ang square ng \sqrt{10} ay 10.

$$\frac{\left(31\sqrt{2}+31\sqrt{5}\right)\left(2\sqrt{10}+3\right)}{31}-\frac{62\sqrt{2}\left(3+2\sqrt{10}\right)}{9-4\times 10}$$

I-multiply ang 4 at 10 para makuha ang 40.

$$\frac{\left(31\sqrt{2}+31\sqrt{5}\right)\left(2\sqrt{10}+3\right)}{31}-\frac{62\sqrt{2}\left(3+2\sqrt{10}\right)}{9-40}$$

I-subtract ang 40 mula sa 9 para makuha ang -31.

$$\frac{\left(31\sqrt{2}+31\sqrt{5}\right)\left(2\sqrt{10}+3\right)}{31}-\frac{62\sqrt{2}\left(3+2\sqrt{10}\right)}{-31}$$

I-divide ang 62\sqrt{2}\left(3+2\sqrt{10}\right) gamit ang -31 para makuha ang -2\sqrt{2}\left(3+2\sqrt{10}\right).

$$\frac{\left(31\sqrt{2}+31\sqrt{5}\right)\left(2\sqrt{10}+3\right)}{31}-\left(-2\sqrt{2}\left(3+2\sqrt{10}\right)\right)$$

Ang kabaliktaran ng -2\sqrt{2}\left(3+2\sqrt{10}\right) ay 2\sqrt{2}\left(3+2\sqrt{10}\right).

$$\frac{\left(31\sqrt{2}+31\sqrt{5}\right)\left(2\sqrt{10}+3\right)}{31}+2\sqrt{2}\left(3+2\sqrt{10}\right)$$

Ilapat ang distributive property sa pamamagitan ng pag-multiply sa bawat term ng 31\sqrt{2}+31\sqrt{5} sa bawat term ng 2\sqrt{10}+3.

$$\frac{62\sqrt{10}\sqrt{2}+93\sqrt{2}+62\sqrt{5}\sqrt{10}+93\sqrt{5}}{31}+2\sqrt{2}\left(3+2\sqrt{10}\right)$$

I-factor out ang 10=2\times 5. I-rewrite ang square root ng product na \sqrt{2\times 5} bilang product ng mga square root na \sqrt{2}\sqrt{5}.

$$\frac{62\sqrt{2}\sqrt{5}\sqrt{2}+93\sqrt{2}+62\sqrt{5}\sqrt{10}+93\sqrt{5}}{31}+2\sqrt{2}\left(3+2\sqrt{10}\right)$$

I-multiply ang \sqrt{2} at \sqrt{2} para makuha ang 2.

$$\frac{62\times 2\sqrt{5}+93\sqrt{2}+62\sqrt{5}\sqrt{10}+93\sqrt{5}}{31}+2\sqrt{2}\left(3+2\sqrt{10}\right)$$

I-multiply ang 62 at 2 para makuha ang 124.

$$\frac{124\sqrt{5}+93\sqrt{2}+62\sqrt{5}\sqrt{10}+93\sqrt{5}}{31}+2\sqrt{2}\left(3+2\sqrt{10}\right)$$

I-factor out ang 10=5\times 2. I-rewrite ang square root ng product na \sqrt{5\times 2} bilang product ng mga square root na \sqrt{5}\sqrt{2}.

$$\frac{124\sqrt{5}+93\sqrt{2}+62\sqrt{5}\sqrt{5}\sqrt{2}+93\sqrt{5}}{31}+2\sqrt{2}\left(3+2\sqrt{10}\right)$$

I-multiply ang \sqrt{5} at \sqrt{5} para makuha ang 5.

$$\frac{124\sqrt{5}+93\sqrt{2}+62\times 5\sqrt{2}+93\sqrt{5}}{31}+2\sqrt{2}\left(3+2\sqrt{10}\right)$$

I-multiply ang 62 at 5 para makuha ang 310.

$$\frac{124\sqrt{5}+93\sqrt{2}+310\sqrt{2}+93\sqrt{5}}{31}+2\sqrt{2}\left(3+2\sqrt{10}\right)$$

Pagsamahin ang 93\sqrt{2} at 310\sqrt{2} para makuha ang 403\sqrt{2}.

$$\frac{124\sqrt{5}+403\sqrt{2}+93\sqrt{5}}{31}+2\sqrt{2}\left(3+2\sqrt{10}\right)$$

Pagsamahin ang 124\sqrt{5} at 93\sqrt{5} para makuha ang 217\sqrt{5}.

$$\frac{217\sqrt{5}+403\sqrt{2}}{31}+2\sqrt{2}\left(3+2\sqrt{10}\right)$$

Hati-hatiin ang bawat termino ng 217\sqrt{5}+403\sqrt{2} sa 31 para makuha ang 7\sqrt{5}+13\sqrt{2}.

$$7\sqrt{5}+13\sqrt{2}+2\sqrt{2}\left(3+2\sqrt{10}\right)$$

Gamitin ang distributive property para i-multiply ang 2\sqrt{2} gamit ang 3+2\sqrt{10}.

$$7\sqrt{5}+13\sqrt{2}+6\sqrt{2}+4\sqrt{10}\sqrt{2}$$

I-factor out ang 10=2\times 5. I-rewrite ang square root ng product na \sqrt{2\times 5} bilang product ng mga square root na \sqrt{2}\sqrt{5}.

$$7\sqrt{5}+13\sqrt{2}+6\sqrt{2}+4\sqrt{2}\sqrt{5}\sqrt{2}$$

I-multiply ang \sqrt{2} at \sqrt{2} para makuha ang 2.

$$7\sqrt{5}+13\sqrt{2}+6\sqrt{2}+4\times 2\sqrt{5}$$

I-multiply ang 4 at 2 para makuha ang 8.

$$7\sqrt{5}+13\sqrt{2}+6\sqrt{2}+8\sqrt{5}$$

Pagsamahin ang 13\sqrt{2} at 6\sqrt{2} para makuha ang 19\sqrt{2}.

$$7\sqrt{5}+19\sqrt{2}+8\sqrt{5}$$

Pagsamahin ang 7\sqrt{5} at 8\sqrt{5} para makuha ang 15\sqrt{5}.

$$15\sqrt{5}+19\sqrt{2}$$

I-factor

$$15 \sqrt{5} + 19 \sqrt{2} = 60.411077348$$