Lutasin ang 1/36(a-2b)^{3}[(a-2)^{2}(a+2)^{2}+4a^{2}-(2-a^2)^2]-ab(11/3b-a)-(1/3a-b)(b^2+a^2)

$$\frac { 1 } { 36 } ( a - 2 b ) ^ { 3 } [ ( a - 2 ) ^ { 2 } ( a + 2 ) ^ { 2 } + 4 a ^ { 2 } - ( 2 - a ^ { 2 } ) ^ { 2 } ] - a b ( \frac { 11 } { 3 } b - a ) - ( \frac { 1 } { 3 } a - b ) ( b ^ { 2 } + a ^ { 2 } )$$

I-evaluate

$$-\frac{5b^{3}}{3}$$

Mga Hakbang ng Solution

Gamitin ang binomial theorem na \left(p-q\right)^{3}=p^{3}-3p^{2}q+3pq^{2}-q^{3} para palawakin ang \left(a-2b\right)^{3}.

$$\frac{1}{36}\left(a^{3}-6a^{2}b+12ab^{2}-8b^{3}\right)\left(\left(a-2\right)^{2}\left(a+2\right)^{2}+4a^{2}-\left(2-a^{2}\right)^{2}\right)-ab\left(\frac{11}{3}b-a\right)-\left(\frac{1}{3}a-b\right)\left(b^{2}+a^{2}\right)$$

Gamitin ang binomial theorem na \left(p-q\right)^{2}=p^{2}-2pq+q^{2} para palawakin ang \left(a-2\right)^{2}.

$$\frac{1}{36}\left(a^{3}-6a^{2}b+12ab^{2}-8b^{3}\right)\left(\left(a^{2}-4a+4\right)\left(a+2\right)^{2}+4a^{2}-\left(2-a^{2}\right)^{2}\right)-ab\left(\frac{11}{3}b-a\right)-\left(\frac{1}{3}a-b\right)\left(b^{2}+a^{2}\right)$$

Gamitin ang binomial theorem na \left(p+q\right)^{2}=p^{2}+2pq+q^{2} para palawakin ang \left(a+2\right)^{2}.

$$\frac{1}{36}\left(a^{3}-6a^{2}b+12ab^{2}-8b^{3}\right)\left(\left(a^{2}-4a+4\right)\left(a^{2}+4a+4\right)+4a^{2}-\left(2-a^{2}\right)^{2}\right)-ab\left(\frac{11}{3}b-a\right)-\left(\frac{1}{3}a-b\right)\left(b^{2}+a^{2}\right)$$

Gamitin ang distributive property para i-multiply ang a^{2}-4a+4 sa a^{2}+4a+4 at para pagsamahin ang magkakatulad na term.

$$\frac{1}{36}\left(a^{3}-6a^{2}b+12ab^{2}-8b^{3}\right)\left(a^{4}-8a^{2}+16+4a^{2}-\left(2-a^{2}\right)^{2}\right)-ab\left(\frac{11}{3}b-a\right)-\left(\frac{1}{3}a-b\right)\left(b^{2}+a^{2}\right)$$

Pagsamahin ang -8a^{2} at 4a^{2} para makuha ang -4a^{2}.

$$\frac{1}{36}\left(a^{3}-6a^{2}b+12ab^{2}-8b^{3}\right)\left(a^{4}-4a^{2}+16-\left(2-a^{2}\right)^{2}\right)-ab\left(\frac{11}{3}b-a\right)-\left(\frac{1}{3}a-b\right)\left(b^{2}+a^{2}\right)$$

Gamitin ang binomial theorem na \left(p-q\right)^{2}=p^{2}-2pq+q^{2} para palawakin ang \left(2-a^{2}\right)^{2}.

$$\frac{1}{36}\left(a^{3}-6a^{2}b+12ab^{2}-8b^{3}\right)\left(a^{4}-4a^{2}+16-\left(4-4a^{2}+\left(a^{2}\right)^{2}\right)\right)-ab\left(\frac{11}{3}b-a\right)-\left(\frac{1}{3}a-b\right)\left(b^{2}+a^{2}\right)$$

Para mag-raise ng power ng numero gamit ang ibang power, i-multiply ang mga exponent. I-multiply ang 2 at 2 para makuha ang 4.

$$\frac{1}{36}\left(a^{3}-6a^{2}b+12ab^{2}-8b^{3}\right)\left(a^{4}-4a^{2}+16-\left(4-4a^{2}+a^{4}\right)\right)-ab\left(\frac{11}{3}b-a\right)-\left(\frac{1}{3}a-b\right)\left(b^{2}+a^{2}\right)$$

Para hanapin ang kabaligtaran ng 4-4a^{2}+a^{4}, hanapin ang kabaligtaran ng bawat term.

$$\frac{1}{36}\left(a^{3}-6a^{2}b+12ab^{2}-8b^{3}\right)\left(a^{4}-4a^{2}+16-4+4a^{2}-a^{4}\right)-ab\left(\frac{11}{3}b-a\right)-\left(\frac{1}{3}a-b\right)\left(b^{2}+a^{2}\right)$$

I-subtract ang 4 mula sa 16 para makuha ang 12.

$$\frac{1}{36}\left(a^{3}-6a^{2}b+12ab^{2}-8b^{3}\right)\left(a^{4}-4a^{2}+12+4a^{2}-a^{4}\right)-ab\left(\frac{11}{3}b-a\right)-\left(\frac{1}{3}a-b\right)\left(b^{2}+a^{2}\right)$$

Pagsamahin ang -4a^{2} at 4a^{2} para makuha ang 0.

$$\frac{1}{36}\left(a^{3}-6a^{2}b+12ab^{2}-8b^{3}\right)\left(a^{4}+12-a^{4}\right)-ab\left(\frac{11}{3}b-a\right)-\left(\frac{1}{3}a-b\right)\left(b^{2}+a^{2}\right)$$

Pagsamahin ang a^{4} at -a^{4} para makuha ang 0.

$$\frac{1}{36}\left(a^{3}-6a^{2}b+12ab^{2}-8b^{3}\right)\times 12-ab\left(\frac{11}{3}b-a\right)-\left(\frac{1}{3}a-b\right)\left(b^{2}+a^{2}\right)$$

I-multiply ang \frac{1}{36} at 12 para makuha ang \frac{1}{3}.

$$\frac{1}{3}\left(a^{3}-6a^{2}b+12ab^{2}-8b^{3}\right)-ab\left(\frac{11}{3}b-a\right)-\left(\frac{1}{3}a-b\right)\left(b^{2}+a^{2}\right)$$

Gamitin ang distributive property para i-multiply ang \frac{1}{3} gamit ang a^{3}-6a^{2}b+12ab^{2}-8b^{3}.

$$\frac{1}{3}a^{3}-2a^{2}b+4ab^{2}-\frac{8}{3}b^{3}-ab\left(\frac{11}{3}b-a\right)-\left(\frac{1}{3}a-b\right)\left(b^{2}+a^{2}\right)$$

Gamitin ang distributive property para i-multiply ang ab gamit ang \frac{11}{3}b-a.

$$\frac{1}{3}a^{3}-2a^{2}b+4ab^{2}-\frac{8}{3}b^{3}-\left(\frac{11}{3}ab^{2}-ba^{2}\right)-\left(\frac{1}{3}a-b\right)\left(b^{2}+a^{2}\right)$$

Para hanapin ang kabaligtaran ng \frac{11}{3}ab^{2}-ba^{2}, hanapin ang kabaligtaran ng bawat term.

$$\frac{1}{3}a^{3}-2a^{2}b+4ab^{2}-\frac{8}{3}b^{3}-\frac{11}{3}ab^{2}+ba^{2}-\left(\frac{1}{3}a-b\right)\left(b^{2}+a^{2}\right)$$

Pagsamahin ang 4ab^{2} at -\frac{11}{3}ab^{2} para makuha ang \frac{1}{3}ab^{2}.

$$\frac{1}{3}a^{3}-2a^{2}b+\frac{1}{3}ab^{2}-\frac{8}{3}b^{3}+ba^{2}-\left(\frac{1}{3}a-b\right)\left(b^{2}+a^{2}\right)$$

Pagsamahin ang -2a^{2}b at ba^{2} para makuha ang -a^{2}b.

$$\frac{1}{3}a^{3}-a^{2}b+\frac{1}{3}ab^{2}-\frac{8}{3}b^{3}-\left(\frac{1}{3}a-b\right)\left(b^{2}+a^{2}\right)$$

Gamitin ang distributive property para i-multiply ang \frac{1}{3}a-b gamit ang b^{2}+a^{2}.

$$\frac{1}{3}a^{3}-a^{2}b+\frac{1}{3}ab^{2}-\frac{8}{3}b^{3}-\left(\frac{1}{3}ab^{2}+\frac{1}{3}a^{3}-b^{3}-ba^{2}\right)$$

Para hanapin ang kabaligtaran ng \frac{1}{3}ab^{2}+\frac{1}{3}a^{3}-b^{3}-ba^{2}, hanapin ang kabaligtaran ng bawat term.

$$\frac{1}{3}a^{3}-a^{2}b+\frac{1}{3}ab^{2}-\frac{8}{3}b^{3}-\frac{1}{3}ab^{2}-\frac{1}{3}a^{3}+b^{3}+ba^{2}$$

Pagsamahin ang \frac{1}{3}ab^{2} at -\frac{1}{3}ab^{2} para makuha ang 0.

$$\frac{1}{3}a^{3}-a^{2}b-\frac{8}{3}b^{3}-\frac{1}{3}a^{3}+b^{3}+ba^{2}$$

Pagsamahin ang \frac{1}{3}a^{3} at -\frac{1}{3}a^{3} para makuha ang 0.

$$-a^{2}b-\frac{8}{3}b^{3}+b^{3}+ba^{2}$$

Pagsamahin ang -\frac{8}{3}b^{3} at b^{3} para makuha ang -\frac{5}{3}b^{3}.

$$-a^{2}b-\frac{5}{3}b^{3}+ba^{2}$$

Pagsamahin ang -a^{2}b at ba^{2} para makuha ang 0.

$$-\frac{5}{3}b^{3}$$

Palawakin

$$-\frac{5b^{3}}{3}$$

Mga Hakbang ng Solution

Gamitin ang binomial theorem na \left(p-q\right)^{3}=p^{3}-3p^{2}q+3pq^{2}-q^{3} para palawakin ang \left(a-2b\right)^{3}.

$$\frac{1}{36}\left(a^{3}-6a^{2}b+12ab^{2}-8b^{3}\right)\left(\left(a-2\right)^{2}\left(a+2\right)^{2}+4a^{2}-\left(2-a^{2}\right)^{2}\right)-ab\left(\frac{11}{3}b-a\right)-\left(\frac{1}{3}a-b\right)\left(b^{2}+a^{2}\right)$$

Gamitin ang binomial theorem na \left(p-q\right)^{2}=p^{2}-2pq+q^{2} para palawakin ang \left(a-2\right)^{2}.

$$\frac{1}{36}\left(a^{3}-6a^{2}b+12ab^{2}-8b^{3}\right)\left(\left(a^{2}-4a+4\right)\left(a+2\right)^{2}+4a^{2}-\left(2-a^{2}\right)^{2}\right)-ab\left(\frac{11}{3}b-a\right)-\left(\frac{1}{3}a-b\right)\left(b^{2}+a^{2}\right)$$

Gamitin ang binomial theorem na \left(p+q\right)^{2}=p^{2}+2pq+q^{2} para palawakin ang \left(a+2\right)^{2}.

$$\frac{1}{36}\left(a^{3}-6a^{2}b+12ab^{2}-8b^{3}\right)\left(\left(a^{2}-4a+4\right)\left(a^{2}+4a+4\right)+4a^{2}-\left(2-a^{2}\right)^{2}\right)-ab\left(\frac{11}{3}b-a\right)-\left(\frac{1}{3}a-b\right)\left(b^{2}+a^{2}\right)$$

Gamitin ang distributive property para i-multiply ang a^{2}-4a+4 sa a^{2}+4a+4 at para pagsamahin ang magkakatulad na term.

$$\frac{1}{36}\left(a^{3}-6a^{2}b+12ab^{2}-8b^{3}\right)\left(a^{4}-8a^{2}+16+4a^{2}-\left(2-a^{2}\right)^{2}\right)-ab\left(\frac{11}{3}b-a\right)-\left(\frac{1}{3}a-b\right)\left(b^{2}+a^{2}\right)$$

Pagsamahin ang -8a^{2} at 4a^{2} para makuha ang -4a^{2}.

$$\frac{1}{36}\left(a^{3}-6a^{2}b+12ab^{2}-8b^{3}\right)\left(a^{4}-4a^{2}+16-\left(2-a^{2}\right)^{2}\right)-ab\left(\frac{11}{3}b-a\right)-\left(\frac{1}{3}a-b\right)\left(b^{2}+a^{2}\right)$$

Gamitin ang binomial theorem na \left(p-q\right)^{2}=p^{2}-2pq+q^{2} para palawakin ang \left(2-a^{2}\right)^{2}.

$$\frac{1}{36}\left(a^{3}-6a^{2}b+12ab^{2}-8b^{3}\right)\left(a^{4}-4a^{2}+16-\left(4-4a^{2}+\left(a^{2}\right)^{2}\right)\right)-ab\left(\frac{11}{3}b-a\right)-\left(\frac{1}{3}a-b\right)\left(b^{2}+a^{2}\right)$$

Para mag-raise ng power ng numero gamit ang ibang power, i-multiply ang mga exponent. I-multiply ang 2 at 2 para makuha ang 4.

$$\frac{1}{36}\left(a^{3}-6a^{2}b+12ab^{2}-8b^{3}\right)\left(a^{4}-4a^{2}+16-\left(4-4a^{2}+a^{4}\right)\right)-ab\left(\frac{11}{3}b-a\right)-\left(\frac{1}{3}a-b\right)\left(b^{2}+a^{2}\right)$$

Para hanapin ang kabaligtaran ng 4-4a^{2}+a^{4}, hanapin ang kabaligtaran ng bawat term.

$$\frac{1}{36}\left(a^{3}-6a^{2}b+12ab^{2}-8b^{3}\right)\left(a^{4}-4a^{2}+16-4+4a^{2}-a^{4}\right)-ab\left(\frac{11}{3}b-a\right)-\left(\frac{1}{3}a-b\right)\left(b^{2}+a^{2}\right)$$

I-subtract ang 4 mula sa 16 para makuha ang 12.

$$\frac{1}{36}\left(a^{3}-6a^{2}b+12ab^{2}-8b^{3}\right)\left(a^{4}-4a^{2}+12+4a^{2}-a^{4}\right)-ab\left(\frac{11}{3}b-a\right)-\left(\frac{1}{3}a-b\right)\left(b^{2}+a^{2}\right)$$

Pagsamahin ang -4a^{2} at 4a^{2} para makuha ang 0.

$$\frac{1}{36}\left(a^{3}-6a^{2}b+12ab^{2}-8b^{3}\right)\left(a^{4}+12-a^{4}\right)-ab\left(\frac{11}{3}b-a\right)-\left(\frac{1}{3}a-b\right)\left(b^{2}+a^{2}\right)$$

Pagsamahin ang a^{4} at -a^{4} para makuha ang 0.

$$\frac{1}{36}\left(a^{3}-6a^{2}b+12ab^{2}-8b^{3}\right)\times 12-ab\left(\frac{11}{3}b-a\right)-\left(\frac{1}{3}a-b\right)\left(b^{2}+a^{2}\right)$$

I-multiply ang \frac{1}{36} at 12 para makuha ang \frac{1}{3}.

$$\frac{1}{3}\left(a^{3}-6a^{2}b+12ab^{2}-8b^{3}\right)-ab\left(\frac{11}{3}b-a\right)-\left(\frac{1}{3}a-b\right)\left(b^{2}+a^{2}\right)$$

Gamitin ang distributive property para i-multiply ang \frac{1}{3} gamit ang a^{3}-6a^{2}b+12ab^{2}-8b^{3}.

$$\frac{1}{3}a^{3}-2a^{2}b+4ab^{2}-\frac{8}{3}b^{3}-ab\left(\frac{11}{3}b-a\right)-\left(\frac{1}{3}a-b\right)\left(b^{2}+a^{2}\right)$$

Gamitin ang distributive property para i-multiply ang ab gamit ang \frac{11}{3}b-a.

$$\frac{1}{3}a^{3}-2a^{2}b+4ab^{2}-\frac{8}{3}b^{3}-\left(\frac{11}{3}ab^{2}-ba^{2}\right)-\left(\frac{1}{3}a-b\right)\left(b^{2}+a^{2}\right)$$

Para hanapin ang kabaligtaran ng \frac{11}{3}ab^{2}-ba^{2}, hanapin ang kabaligtaran ng bawat term.

$$\frac{1}{3}a^{3}-2a^{2}b+4ab^{2}-\frac{8}{3}b^{3}-\frac{11}{3}ab^{2}+ba^{2}-\left(\frac{1}{3}a-b\right)\left(b^{2}+a^{2}\right)$$

Pagsamahin ang 4ab^{2} at -\frac{11}{3}ab^{2} para makuha ang \frac{1}{3}ab^{2}.

$$\frac{1}{3}a^{3}-2a^{2}b+\frac{1}{3}ab^{2}-\frac{8}{3}b^{3}+ba^{2}-\left(\frac{1}{3}a-b\right)\left(b^{2}+a^{2}\right)$$

Pagsamahin ang -2a^{2}b at ba^{2} para makuha ang -a^{2}b.

$$\frac{1}{3}a^{3}-a^{2}b+\frac{1}{3}ab^{2}-\frac{8}{3}b^{3}-\left(\frac{1}{3}a-b\right)\left(b^{2}+a^{2}\right)$$

Gamitin ang distributive property para i-multiply ang \frac{1}{3}a-b gamit ang b^{2}+a^{2}.

$$\frac{1}{3}a^{3}-a^{2}b+\frac{1}{3}ab^{2}-\frac{8}{3}b^{3}-\left(\frac{1}{3}ab^{2}+\frac{1}{3}a^{3}-b^{3}-ba^{2}\right)$$

Para hanapin ang kabaligtaran ng \frac{1}{3}ab^{2}+\frac{1}{3}a^{3}-b^{3}-ba^{2}, hanapin ang kabaligtaran ng bawat term.

$$\frac{1}{3}a^{3}-a^{2}b+\frac{1}{3}ab^{2}-\frac{8}{3}b^{3}-\frac{1}{3}ab^{2}-\frac{1}{3}a^{3}+b^{3}+ba^{2}$$

Pagsamahin ang \frac{1}{3}ab^{2} at -\frac{1}{3}ab^{2} para makuha ang 0.

$$\frac{1}{3}a^{3}-a^{2}b-\frac{8}{3}b^{3}-\frac{1}{3}a^{3}+b^{3}+ba^{2}$$

Pagsamahin ang \frac{1}{3}a^{3} at -\frac{1}{3}a^{3} para makuha ang 0.

$$-a^{2}b-\frac{8}{3}b^{3}+b^{3}+ba^{2}$$

Pagsamahin ang -\frac{8}{3}b^{3} at b^{3} para makuha ang -\frac{5}{3}b^{3}.

$$-a^{2}b-\frac{5}{3}b^{3}+ba^{2}$$

Pagsamahin ang -a^{2}b at ba^{2} para makuha ang 0.

$$-\frac{5}{3}b^{3}$$