حل {l}{cot(θ)=1/8}{a={({(1+cos(θ))}{(1-cos(θ))})}}{b=a}{text{Solvefor}ctext{where}}{c=b}

$$\left. \begin{array} { l } { \cot(\theta) = \frac{1}{8} }\\ { a = {({(1 + \cos(\theta))} {(1 - \cos(\theta))})} }\\ { b = a }\\ { \text{Solve for } c \text{ where} } \\ { c = b } \end{array} \right.$$

برای θ،a،b،c حل کنید

$$\theta =2\pi n_{1}+\arctan(8)\text{, }n_{1}\in \mathrm{Z}\text{, }a=\frac{64}{65}\approx 0.984615385\text{, }b=\frac{64}{65}\approx 0.984615385\text{, }c=\frac{64}{65}\approx 0.984615385$$

$$\theta =2\pi n_{2}+\pi +\arctan(8)\text{, }n_{2}\in \mathrm{Z}\text{, }a=\frac{64}{65}\approx 0.984615385\text{, }b=\frac{64}{65}\approx 0.984615385\text{, }c=\frac{64}{65}\approx 0.984615385$$