Resolver 20(1+2x/100)*25*20*(1-3x/10div100)+5(1+6x/100)*4*20*(1-x/4div100)=(20*(1+2xdiv100)*25+5*(1+6xdiv100)*4)*20*(1-5xdiv18div100)

$$20(1+ \frac{ 2x }{ 100 } ) \times 25 \times 20 \times (1- \frac{ 3x }{ 10 } \div 100)+5(1+ \frac{ 6x }{ 100 } ) \times 4 \times 20 \times (1- \frac{ x }{ 4 } \div 100)=(20 \times (1+2x \div 100) \times 25+5 \times (1+6x \div 100) \times 4) \times 20 \times (1-5x \div 18 \div 100)$$

Ebatzi: x

$$x = -\frac{950}{17} = -55\frac{15}{17} \approx -55.882352941$$

$$x=0$$

Formula koadratikoaren bidezko ebazpidea

Biderkatu ekuazioaren bi aldeak honekin: 100.

$$2000\left(1+\frac{2x}{100}\right)\times 25\times 20\left(1-\frac{\frac{3x}{10}}{100}\right)+500\left(1+\frac{6x}{100}\right)\times 4\times 20\left(1-\frac{\frac{x}{4}}{100}\right)=100\left(20\left(1+\frac{2x}{100}\right)\times 25+5\left(1+\frac{6x}{100}\right)\times 4\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

\frac{1}{50}x lortzeko, zatitu 2x 100 balioarekin.

$$2000\left(1+\frac{1}{50}x\right)\times 25\times 20\left(1-\frac{\frac{3x}{10}}{100}\right)+500\left(1+\frac{6x}{100}\right)\times 4\times 20\left(1-\frac{\frac{x}{4}}{100}\right)=100\left(20\left(1+\frac{2x}{100}\right)\times 25+5\left(1+\frac{6x}{100}\right)\times 4\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

50000 lortzeko, biderkatu 2000 eta 25.

$$50000\left(1+\frac{1}{50}x\right)\times 20\left(1-\frac{\frac{3x}{10}}{100}\right)+500\left(1+\frac{6x}{100}\right)\times 4\times 20\left(1-\frac{\frac{x}{4}}{100}\right)=100\left(20\left(1+\frac{2x}{100}\right)\times 25+5\left(1+\frac{6x}{100}\right)\times 4\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

1000000 lortzeko, biderkatu 50000 eta 20.

$$1000000\left(1+\frac{1}{50}x\right)\left(1-\frac{\frac{3x}{10}}{100}\right)+500\left(1+\frac{6x}{100}\right)\times 4\times 20\left(1-\frac{\frac{x}{4}}{100}\right)=100\left(20\left(1+\frac{2x}{100}\right)\times 25+5\left(1+\frac{6x}{100}\right)\times 4\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

Erabili banaketa-propietatea 1000000 eta 1+\frac{1}{50}x biderkatzeko.

$$\left(1000000+1000000\times \frac{1}{50}x\right)\left(1-\frac{\frac{3x}{10}}{100}\right)+500\left(1+\frac{6x}{100}\right)\times 4\times 20\left(1-\frac{\frac{x}{4}}{100}\right)=100\left(20\left(1+\frac{2x}{100}\right)\times 25+5\left(1+\frac{6x}{100}\right)\times 4\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

\frac{1000000}{50} lortzeko, biderkatu 1000000 eta \frac{1}{50}.

$$\left(1000000+\frac{1000000}{50}x\right)\left(1-\frac{\frac{3x}{10}}{100}\right)+500\left(1+\frac{6x}{100}\right)\times 4\times 20\left(1-\frac{\frac{x}{4}}{100}\right)=100\left(20\left(1+\frac{2x}{100}\right)\times 25+5\left(1+\frac{6x}{100}\right)\times 4\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

20000 lortzeko, zatitu 1000000 50 balioarekin.

$$\left(1000000+20000x\right)\left(1-\frac{\frac{3x}{10}}{100}\right)+500\left(1+\frac{6x}{100}\right)\times 4\times 20\left(1-\frac{\frac{x}{4}}{100}\right)=100\left(20\left(1+\frac{2x}{100}\right)\times 25+5\left(1+\frac{6x}{100}\right)\times 4\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

Aplikatu banaketa-propietatea, 1000000+20000x funtzioaren gaiak 1-\frac{\frac{3x}{10}}{100} funtzioaren gaiekin biderkatuz.

$$1000000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+20000x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+500\left(1+\frac{6x}{100}\right)\times 4\times 20\left(1-\frac{\frac{x}{4}}{100}\right)=100\left(20\left(1+\frac{2x}{100}\right)\times 25+5\left(1+\frac{6x}{100}\right)\times 4\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

\frac{3}{50}x lortzeko, zatitu 6x 100 balioarekin.

$$1000000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+20000x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+500\left(1+\frac{3}{50}x\right)\times 4\times 20\left(1-\frac{\frac{x}{4}}{100}\right)=100\left(20\left(1+\frac{2x}{100}\right)\times 25+5\left(1+\frac{6x}{100}\right)\times 4\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

2000 lortzeko, biderkatu 500 eta 4.

$$1000000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+20000x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+2000\left(1+\frac{3}{50}x\right)\times 20\left(1-\frac{\frac{x}{4}}{100}\right)=100\left(20\left(1+\frac{2x}{100}\right)\times 25+5\left(1+\frac{6x}{100}\right)\times 4\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

40000 lortzeko, biderkatu 2000 eta 20.

$$1000000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+20000x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+40000\left(1+\frac{3}{50}x\right)\left(1-\frac{\frac{x}{4}}{100}\right)=100\left(20\left(1+\frac{2x}{100}\right)\times 25+5\left(1+\frac{6x}{100}\right)\times 4\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

Erabili banaketa-propietatea 40000 eta 1+\frac{3}{50}x biderkatzeko.

$$1000000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+20000x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+\left(40000+40000\times \frac{3}{50}x\right)\left(1-\frac{\frac{x}{4}}{100}\right)=100\left(20\left(1+\frac{2x}{100}\right)\times 25+5\left(1+\frac{6x}{100}\right)\times 4\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

Adierazi 40000\times \frac{3}{50} frakzio bakar gisa.

$$1000000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+20000x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+\left(40000+\frac{40000\times 3}{50}x\right)\left(1-\frac{\frac{x}{4}}{100}\right)=100\left(20\left(1+\frac{2x}{100}\right)\times 25+5\left(1+\frac{6x}{100}\right)\times 4\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

120000 lortzeko, biderkatu 40000 eta 3.

$$1000000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+20000x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+\left(40000+\frac{120000}{50}x\right)\left(1-\frac{\frac{x}{4}}{100}\right)=100\left(20\left(1+\frac{2x}{100}\right)\times 25+5\left(1+\frac{6x}{100}\right)\times 4\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

2400 lortzeko, zatitu 120000 50 balioarekin.

$$1000000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+20000x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+\left(40000+2400x\right)\left(1-\frac{\frac{x}{4}}{100}\right)=100\left(20\left(1+\frac{2x}{100}\right)\times 25+5\left(1+\frac{6x}{100}\right)\times 4\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

Aplikatu banaketa-propietatea, 40000+2400x funtzioaren gaiak 1-\frac{\frac{x}{4}}{100} funtzioaren gaiekin biderkatuz.

$$1000000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+20000x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+40000+40000\left(-\frac{\frac{x}{4}}{100}\right)+2400x+2400x\left(-\frac{\frac{x}{4}}{100}\right)=100\left(20\left(1+\frac{2x}{100}\right)\times 25+5\left(1+\frac{6x}{100}\right)\times 4\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

1040000 lortzeko, gehitu 1000000 eta 40000.

$$1040000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+20000x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+40000\left(-\frac{\frac{x}{4}}{100}\right)+2400x+2400x\left(-\frac{\frac{x}{4}}{100}\right)=100\left(20\left(1+\frac{2x}{100}\right)\times 25+5\left(1+\frac{6x}{100}\right)\times 4\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

22400x lortzeko, konbinatu 20000x eta 2400x.

$$1040000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+22400x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+40000\left(-\frac{\frac{x}{4}}{100}\right)+2400x\left(-\frac{\frac{x}{4}}{100}\right)=100\left(20\left(1+\frac{2x}{100}\right)\times 25+5\left(1+\frac{6x}{100}\right)\times 4\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

\frac{1}{50}x lortzeko, zatitu 2x 100 balioarekin.

$$1040000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+22400x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+40000\left(-\frac{\frac{x}{4}}{100}\right)+2400x\left(-\frac{\frac{x}{4}}{100}\right)=100\left(20\left(1+\frac{1}{50}x\right)\times 25+5\left(1+\frac{6x}{100}\right)\times 4\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

500 lortzeko, biderkatu 20 eta 25.

$$1040000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+22400x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+40000\left(-\frac{\frac{x}{4}}{100}\right)+2400x\left(-\frac{\frac{x}{4}}{100}\right)=100\left(500\left(1+\frac{1}{50}x\right)+5\left(1+\frac{6x}{100}\right)\times 4\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

Erabili banaketa-propietatea 500 eta 1+\frac{1}{50}x biderkatzeko.

$$1040000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+22400x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+40000\left(-\frac{\frac{x}{4}}{100}\right)+2400x\left(-\frac{\frac{x}{4}}{100}\right)=100\left(500+500\times \frac{1}{50}x+5\left(1+\frac{6x}{100}\right)\times 4\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

\frac{500}{50} lortzeko, biderkatu 500 eta \frac{1}{50}.

$$1040000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+22400x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+40000\left(-\frac{\frac{x}{4}}{100}\right)+2400x\left(-\frac{\frac{x}{4}}{100}\right)=100\left(500+\frac{500}{50}x+5\left(1+\frac{6x}{100}\right)\times 4\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

10 lortzeko, zatitu 500 50 balioarekin.

$$1040000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+22400x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+40000\left(-\frac{\frac{x}{4}}{100}\right)+2400x\left(-\frac{\frac{x}{4}}{100}\right)=100\left(500+10x+5\left(1+\frac{6x}{100}\right)\times 4\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

\frac{3}{50}x lortzeko, zatitu 6x 100 balioarekin.

$$1040000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+22400x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+40000\left(-\frac{\frac{x}{4}}{100}\right)+2400x\left(-\frac{\frac{x}{4}}{100}\right)=100\left(500+10x+5\left(1+\frac{3}{50}x\right)\times 4\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

20 lortzeko, biderkatu 5 eta 4.

$$1040000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+22400x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+40000\left(-\frac{\frac{x}{4}}{100}\right)+2400x\left(-\frac{\frac{x}{4}}{100}\right)=100\left(500+10x+20\left(1+\frac{3}{50}x\right)\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

Erabili banaketa-propietatea 20 eta 1+\frac{3}{50}x biderkatzeko.

$$1040000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+22400x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+40000\left(-\frac{\frac{x}{4}}{100}\right)+2400x\left(-\frac{\frac{x}{4}}{100}\right)=100\left(500+10x+20+20\times \frac{3}{50}x\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

Adierazi 20\times \frac{3}{50} frakzio bakar gisa.

$$1040000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+22400x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+40000\left(-\frac{\frac{x}{4}}{100}\right)+2400x\left(-\frac{\frac{x}{4}}{100}\right)=100\left(500+10x+20+\frac{20\times 3}{50}x\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

60 lortzeko, biderkatu 20 eta 3.

$$1040000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+22400x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+40000\left(-\frac{\frac{x}{4}}{100}\right)+2400x\left(-\frac{\frac{x}{4}}{100}\right)=100\left(500+10x+20+\frac{60}{50}x\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

Murriztu \frac{60}{50} zatikia gai txikienera, 10 bakanduta eta ezeztatuta.

$$1040000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+22400x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+40000\left(-\frac{\frac{x}{4}}{100}\right)+2400x\left(-\frac{\frac{x}{4}}{100}\right)=100\left(500+10x+20+\frac{6}{5}x\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

520 lortzeko, gehitu 500 eta 20.

$$1040000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+22400x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+40000\left(-\frac{\frac{x}{4}}{100}\right)+2400x\left(-\frac{\frac{x}{4}}{100}\right)=100\left(520+10x+\frac{6}{5}x\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

\frac{56}{5}x lortzeko, konbinatu 10x eta \frac{6}{5}x.

$$1040000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+22400x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+40000\left(-\frac{\frac{x}{4}}{100}\right)+2400x\left(-\frac{\frac{x}{4}}{100}\right)=100\left(520+\frac{56}{5}x\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

2000 lortzeko, biderkatu 100 eta 20.

$$1040000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+22400x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+40000\left(-\frac{\frac{x}{4}}{100}\right)+2400x\left(-\frac{\frac{x}{4}}{100}\right)=2000\left(520+\frac{56}{5}x\right)\left(1-\frac{\frac{5x}{18}}{100}\right)$$

Erabili banaketa-propietatea 2000 eta 520+\frac{56}{5}x biderkatzeko.

$$1040000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+22400x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+40000\left(-\frac{\frac{x}{4}}{100}\right)+2400x\left(-\frac{\frac{x}{4}}{100}\right)=\left(1040000+2000\times \frac{56}{5}x\right)\left(1-\frac{\frac{5x}{18}}{100}\right)$$

Adierazi 2000\times \frac{56}{5} frakzio bakar gisa.

$$1040000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+22400x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+40000\left(-\frac{\frac{x}{4}}{100}\right)+2400x\left(-\frac{\frac{x}{4}}{100}\right)=\left(1040000+\frac{2000\times 56}{5}x\right)\left(1-\frac{\frac{5x}{18}}{100}\right)$$

112000 lortzeko, biderkatu 2000 eta 56.

$$1040000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+22400x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+40000\left(-\frac{\frac{x}{4}}{100}\right)+2400x\left(-\frac{\frac{x}{4}}{100}\right)=\left(1040000+\frac{112000}{5}x\right)\left(1-\frac{\frac{5x}{18}}{100}\right)$$

22400 lortzeko, zatitu 112000 5 balioarekin.

$$1040000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+22400x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+40000\left(-\frac{\frac{x}{4}}{100}\right)+2400x\left(-\frac{\frac{x}{4}}{100}\right)=\left(1040000+22400x\right)\left(1-\frac{\frac{5x}{18}}{100}\right)$$

Aplikatu banaketa-propietatea, 1040000+22400x funtzioaren gaiak 1-\frac{\frac{5x}{18}}{100} funtzioaren gaiekin biderkatuz.

$$1040000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+22400x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+40000\left(-\frac{\frac{x}{4}}{100}\right)+2400x\left(-\frac{\frac{x}{4}}{100}\right)=1040000+1040000\left(-\frac{\frac{5x}{18}}{100}\right)+22400x+22400x\left(-\frac{\frac{5x}{18}}{100}\right)$$

Kendu 1040000 bi aldeetatik.

$$1040000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+22400x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+40000\left(-\frac{\frac{x}{4}}{100}\right)+2400x\left(-\frac{\frac{x}{4}}{100}\right)-1040000=1040000\left(-\frac{\frac{5x}{18}}{100}\right)+22400x+22400x\left(-\frac{\frac{5x}{18}}{100}\right)$$

0 lortzeko, 1040000 balioari kendu 1040000.

$$1000000\left(-\frac{\frac{3x}{10}}{100}\right)+22400x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+40000\left(-\frac{\frac{x}{4}}{100}\right)+2400x\left(-\frac{\frac{x}{4}}{100}\right)=1040000\left(-\frac{\frac{5x}{18}}{100}\right)+22400x+22400x\left(-\frac{\frac{5x}{18}}{100}\right)$$

Kendu 1040000\left(-\frac{\frac{5x}{18}}{100}\right) bi aldeetatik.

$$1000000\left(-\frac{\frac{3x}{10}}{100}\right)+22400x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+40000\left(-\frac{\frac{x}{4}}{100}\right)+2400x\left(-\frac{\frac{x}{4}}{100}\right)-1040000\left(-\frac{\frac{5x}{18}}{100}\right)=22400x+22400x\left(-\frac{\frac{5x}{18}}{100}\right)$$

Kendu 22400x bi aldeetatik.

$$1000000\left(-\frac{\frac{3x}{10}}{100}\right)+22400x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+40000\left(-\frac{\frac{x}{4}}{100}\right)+2400x\left(-\frac{\frac{x}{4}}{100}\right)-1040000\left(-\frac{\frac{5x}{18}}{100}\right)-22400x=22400x\left(-\frac{\frac{5x}{18}}{100}\right)$$

Kendu 22400x\left(-\frac{\frac{5x}{18}}{100}\right) bi aldeetatik.

$$1000000\left(-\frac{\frac{3x}{10}}{100}\right)+22400x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+40000\left(-\frac{\frac{x}{4}}{100}\right)+2400x\left(-\frac{\frac{x}{4}}{100}\right)-1040000\left(-\frac{\frac{5x}{18}}{100}\right)-22400x-22400x\left(-\frac{\frac{5x}{18}}{100}\right)=0$$

Biderkatu ekuazioaren bi aldeak honekin: 100.

$$100\left(1000000\left(-\frac{\frac{3x}{10}}{100}\right)+22400x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+40000\left(-\frac{\frac{x}{4}}{100}\right)+2400x\left(-\frac{\frac{x}{4}}{100}\right)-1040000\left(-\frac{\frac{5x}{18}}{100}\right)-22400x\right)-2240000x\left(-\frac{\frac{5x}{18}}{100}\right)=0$$

Berrantolatu gaiak.

$$100\left(2400x\left(-\frac{x}{4\times 100}\right)+20000x\left(-\frac{3x}{10\times 100}\right)+40000\left(-\frac{x}{4\times 100}\right)+1000000\left(-\frac{3x}{10\times 100}\right)+22400x-1040000\left(-\frac{5x}{18\times 100}\right)-22400x\right)-2240000x\left(-\frac{5x}{18\times 100}\right)=0$$

-40000 lortzeko, biderkatu 40000 eta -1. -1000000 lortzeko, biderkatu 1000000 eta -1. -1040000 lortzeko, biderkatu -1 eta 1040000.

$$100\left(2400x\left(-1\right)\times \frac{x}{4\times 100}+20000x\left(-1\right)\times \frac{3x}{10\times 100}-40000\times \frac{x}{4\times 100}-1000000\times \frac{3x}{10\times 100}+22400x-1040000\left(-1\right)\times \frac{5x}{18\times 100}-22400x\right)-2240000x\left(-1\right)\times \frac{5x}{18\times 100}=0$$

-2400 lortzeko, biderkatu 2400 eta -1.

$$100\left(-2400x\times \frac{x}{4\times 100}+20000x\left(-1\right)\times \frac{3x}{10\times 100}-40000\times \frac{x}{4\times 100}-1000000\times \frac{3x}{10\times 100}+22400x-1040000\left(-1\right)\times \frac{5x}{18\times 100}-22400x\right)-2240000x\left(-1\right)\times \frac{5x}{18\times 100}=0$$

400 lortzeko, biderkatu 4 eta 100.

$$100\left(-2400x\times \frac{x}{400}+20000x\left(-1\right)\times \frac{3x}{10\times 100}-40000\times \frac{x}{4\times 100}-1000000\times \frac{3x}{10\times 100}+22400x-1040000\left(-1\right)\times \frac{5x}{18\times 100}-22400x\right)-2240000x\left(-1\right)\times \frac{5x}{18\times 100}=0$$

Deuseztatu 2400 eta 400 balioen faktore komunetan handiena (400).

$$100\left(-6xx+20000x\left(-1\right)\times \frac{3x}{10\times 100}-40000\times \frac{x}{4\times 100}-1000000\times \frac{3x}{10\times 100}+22400x-1040000\left(-1\right)\times \frac{5x}{18\times 100}-22400x\right)-2240000x\left(-1\right)\times \frac{5x}{18\times 100}=0$$

-20000 lortzeko, biderkatu 20000 eta -1.

$$100\left(-6xx-20000x\times \frac{3x}{10\times 100}-40000\times \frac{x}{4\times 100}-1000000\times \frac{3x}{10\times 100}+22400x-1040000\left(-1\right)\times \frac{5x}{18\times 100}-22400x\right)-2240000x\left(-1\right)\times \frac{5x}{18\times 100}=0$$

1000 lortzeko, biderkatu 10 eta 100.

$$100\left(-6xx-20000x\times \frac{3x}{1000}-40000\times \frac{x}{4\times 100}-1000000\times \frac{3x}{10\times 100}+22400x-1040000\left(-1\right)\times \frac{5x}{18\times 100}-22400x\right)-2240000x\left(-1\right)\times \frac{5x}{18\times 100}=0$$

Deuseztatu 20000 eta 1000 balioen faktore komunetan handiena (1000).

$$100\left(-6xx-20\times 3xx-40000\times \frac{x}{4\times 100}-1000000\times \frac{3x}{10\times 100}+22400x-1040000\left(-1\right)\times \frac{5x}{18\times 100}-22400x\right)-2240000x\left(-1\right)\times \frac{5x}{18\times 100}=0$$

400 lortzeko, biderkatu 4 eta 100.

$$100\left(-6xx-20\times 3xx-40000\times \frac{x}{400}-1000000\times \frac{3x}{10\times 100}+22400x-1040000\left(-1\right)\times \frac{5x}{18\times 100}-22400x\right)-2240000x\left(-1\right)\times \frac{5x}{18\times 100}=0$$

Deuseztatu 40000 eta 400 balioen faktore komunetan handiena (400).

$$100\left(-6xx-20\times 3xx-100x-1000000\times \frac{3x}{10\times 100}+22400x-1040000\left(-1\right)\times \frac{5x}{18\times 100}-22400x\right)-2240000x\left(-1\right)\times \frac{5x}{18\times 100}=0$$

1000 lortzeko, biderkatu 10 eta 100.

$$100\left(-6xx-20\times 3xx-100x-1000000\times \frac{3x}{1000}+22400x-1040000\left(-1\right)\times \frac{5x}{18\times 100}-22400x\right)-2240000x\left(-1\right)\times \frac{5x}{18\times 100}=0$$

Deuseztatu 1000000 eta 1000 balioen faktore komunetan handiena (1000).

$$100\left(-6xx-20\times 3xx-100x-1000\times 3x+22400x-1040000\left(-1\right)\times \frac{5x}{18\times 100}-22400x\right)-2240000x\left(-1\right)\times \frac{5x}{18\times 100}=0$$

22300x lortzeko, konbinatu -100x eta 22400x.

$$100\left(-6xx-20\times 3xx+22300x-1000\times 3x-1040000\left(-1\right)\times \frac{5x}{18\times 100}-22400x\right)-2240000x\left(-1\right)\times \frac{5x}{18\times 100}=0$$

1040000 lortzeko, biderkatu -1040000 eta -1.

$$100\left(-6xx-20\times 3xx+22300x-1000\times 3x+1040000\times \frac{5x}{18\times 100}-22400x\right)-2240000x\left(-1\right)\times \frac{5x}{18\times 100}=0$$

Sinplifikatu 5 zenbakitzailean eta izendatzailean.

$$100\left(-6xx-20\times 3xx+22300x-1000\times 3x+1040000\times \frac{x}{18\times 20}-22400x\right)-2240000x\left(-1\right)\times \frac{5x}{18\times 100}=0$$

360 lortzeko, biderkatu 18 eta 20.

$$100\left(-6xx-20\times 3xx+22300x-1000\times 3x+1040000\times \frac{x}{360}-22400x\right)-2240000x\left(-1\right)\times \frac{5x}{18\times 100}=0$$

Adierazi 1040000\times \frac{x}{360} frakzio bakar gisa.

$$100\left(-6xx-20\times 3xx+22300x-1000\times 3x+\frac{1040000x}{360}-22400x\right)-2240000x\left(-1\right)\times \frac{5x}{18\times 100}=0$$

-100x lortzeko, konbinatu 22300x eta -22400x.

$$100\left(-6xx-20\times 3xx-100x-1000\times 3x+\frac{1040000x}{360}\right)-2240000x\left(-1\right)\times \frac{5x}{18\times 100}=0$$

-60 lortzeko, biderkatu -20 eta 3. -3000 lortzeko, biderkatu -1000 eta 3.

$$100\left(-6xx-60xx-100x-3000x+\frac{1040000x}{360}\right)-2240000x\left(-1\right)\times \frac{5x}{18\times 100}=0$$

-66xx lortzeko, konbinatu -6xx eta -60xx.

$$100\left(-66xx-100x-3000x+\frac{1040000x}{360}\right)-2240000x\left(-1\right)\times \frac{5x}{18\times 100}=0$$

-3100x lortzeko, konbinatu -100x eta -3000x.

$$100\left(-66xx-3100x+\frac{1040000x}{360}\right)-2240000x\left(-1\right)\times \frac{5x}{18\times 100}=0$$

Erabili banaketa-propietatea 100 eta -66xx-3100x+\frac{1040000x}{360} biderkatzeko.

$$-6600x^{2}-310000x+100\times \frac{1040000x}{360}-2240000x\left(-1\right)\times \frac{5x}{18\times 100}=0$$

\frac{26000}{9}x lortzeko, zatitu 1040000x 360 balioarekin.

$$-6600x^{2}-310000x+100\times \frac{26000}{9}x-2240000x\left(-1\right)\times \frac{5x}{18\times 100}=0$$

Adierazi 100\times \frac{26000}{9} frakzio bakar gisa.

$$-6600x^{2}-310000x+\frac{100\times 26000}{9}x-2240000x\left(-1\right)\times \frac{5x}{18\times 100}=0$$

2600000 lortzeko, biderkatu 100 eta 26000.

$$-6600x^{2}-310000x+\frac{2600000}{9}x-2240000x\left(-1\right)\times \frac{5x}{18\times 100}=0$$

-\frac{190000}{9}x lortzeko, konbinatu -310000x eta \frac{2600000}{9}x.

$$-6600x^{2}-\frac{190000}{9}x-2240000x\left(-1\right)\times \frac{5x}{18\times 100}=0$$

2240000 lortzeko, biderkatu -2240000 eta -1.

$$-6600x^{2}-\frac{190000}{9}x+2240000x\times \frac{5x}{18\times 100}=0$$

Sinplifikatu 5 zenbakitzailean eta izendatzailean.

$$-6600x^{2}-\frac{190000}{9}x+2240000x\times \frac{x}{18\times 20}=0$$

360 lortzeko, biderkatu 18 eta 20.

$$-6600x^{2}-\frac{190000}{9}x+2240000x\times \frac{x}{360}=0$$

Adierazi 2240000\times \frac{x}{360} frakzio bakar gisa.

$$-6600x^{2}-\frac{190000}{9}x+\frac{2240000x}{360}x=0$$

\frac{56000}{9}x lortzeko, zatitu 2240000x 360 balioarekin.

$$-6600x^{2}-\frac{190000}{9}x+\frac{56000}{9}xx=0$$

x^{2} lortzeko, biderkatu x eta x.

$$-6600x^{2}-\frac{190000}{9}x+\frac{56000}{9}x^{2}=0$$

-\frac{3400}{9}x^{2} lortzeko, konbinatu -6600x^{2} eta \frac{56000}{9}x^{2}.

$$-\frac{3400}{9}x^{2}-\frac{190000}{9}x=0$$

Estandarra da ekuazioaren forma: ax^{2}+bx+c=0. Ordeztu -\frac{3400}{9} balioa a balioarekin, -\frac{190000}{9} balioa b balioarekin, eta 0 balioa c balioarekin formula koadratikoan (\frac{-b±\sqrt{b^{2}-4ac}}{2a}).

$$x=\frac{-\left(-\frac{190000}{9}\right)±\sqrt{\left(-\frac{190000}{9}\right)^{2}}}{2\left(-\frac{3400}{9}\right)}$$

Atera \left(-\frac{190000}{9}\right)^{2} balioaren erro karratua.

$$x=\frac{-\left(-\frac{190000}{9}\right)±\frac{190000}{9}}{2\left(-\frac{3400}{9}\right)}$$

-\frac{190000}{9} zenbakiaren aurkakoa \frac{190000}{9} da.

$$x=\frac{\frac{190000}{9}±\frac{190000}{9}}{2\left(-\frac{3400}{9}\right)}$$

Egin 2 bider -\frac{3400}{9}.

$$x=\frac{\frac{190000}{9}±\frac{190000}{9}}{-\frac{6800}{9}}$$

Orain, ebatzi x=\frac{\frac{190000}{9}±\frac{190000}{9}}{-\frac{6800}{9}} ekuazioa ± plus denean. Gehitu \frac{190000}{9} eta \frac{190000}{9} izendatzaile komun bat aurkituz eta zenbakitzaileak gehituz. Gero, ahal dela, sinplifikatu frakzioa, ahalik eta gai gutxien izan ditzan.

$$x=\frac{\frac{380000}{9}}{-\frac{6800}{9}}$$

Zatitu \frac{380000}{9} balioa -\frac{6800}{9} frakzioarekin, \frac{380000}{9} balioa -\frac{6800}{9} frakzioaren frakzio erreziprokoarekin biderkatuz.

$$x=-\frac{950}{17}$$

Orain, ebatzi x=\frac{\frac{190000}{9}±\frac{190000}{9}}{-\frac{6800}{9}} ekuazioa ± minus denean. Egin \frac{190000}{9} ken \frac{190000}{9} izendatzaile komuna aurkitu, eta zenbakitzaileen arteko kenketa eginda. Gero, ahal dela, sinplifikatu zatikia, ahalik eta gai gutxien izan ditzan.

$$x=\frac{0}{-\frac{6800}{9}}$$

Zatitu 0 balioa -\frac{6800}{9} frakzioarekin, 0 balioa -\frac{6800}{9} frakzioaren frakzio erreziprokoarekin biderkatuz.

$$x=0$$

Ebatzi da ekuazioa.

$$x=-\frac{950}{17} x=0$$

Karratua osatzeko urratsak

Biderkatu ekuazioaren bi aldeak honekin: 100.

$$2000\left(1+\frac{2x}{100}\right)\times 25\times 20\left(1-\frac{\frac{3x}{10}}{100}\right)+500\left(1+\frac{6x}{100}\right)\times 4\times 20\left(1-\frac{\frac{x}{4}}{100}\right)=100\left(20\left(1+\frac{2x}{100}\right)\times 25+5\left(1+\frac{6x}{100}\right)\times 4\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

\frac{1}{50}x lortzeko, zatitu 2x 100 balioarekin.

$$2000\left(1+\frac{1}{50}x\right)\times 25\times 20\left(1-\frac{\frac{3x}{10}}{100}\right)+500\left(1+\frac{6x}{100}\right)\times 4\times 20\left(1-\frac{\frac{x}{4}}{100}\right)=100\left(20\left(1+\frac{2x}{100}\right)\times 25+5\left(1+\frac{6x}{100}\right)\times 4\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

50000 lortzeko, biderkatu 2000 eta 25.

$$50000\left(1+\frac{1}{50}x\right)\times 20\left(1-\frac{\frac{3x}{10}}{100}\right)+500\left(1+\frac{6x}{100}\right)\times 4\times 20\left(1-\frac{\frac{x}{4}}{100}\right)=100\left(20\left(1+\frac{2x}{100}\right)\times 25+5\left(1+\frac{6x}{100}\right)\times 4\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

1000000 lortzeko, biderkatu 50000 eta 20.

$$1000000\left(1+\frac{1}{50}x\right)\left(1-\frac{\frac{3x}{10}}{100}\right)+500\left(1+\frac{6x}{100}\right)\times 4\times 20\left(1-\frac{\frac{x}{4}}{100}\right)=100\left(20\left(1+\frac{2x}{100}\right)\times 25+5\left(1+\frac{6x}{100}\right)\times 4\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

Erabili banaketa-propietatea 1000000 eta 1+\frac{1}{50}x biderkatzeko.

$$\left(1000000+1000000\times \frac{1}{50}x\right)\left(1-\frac{\frac{3x}{10}}{100}\right)+500\left(1+\frac{6x}{100}\right)\times 4\times 20\left(1-\frac{\frac{x}{4}}{100}\right)=100\left(20\left(1+\frac{2x}{100}\right)\times 25+5\left(1+\frac{6x}{100}\right)\times 4\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

\frac{1000000}{50} lortzeko, biderkatu 1000000 eta \frac{1}{50}.

$$\left(1000000+\frac{1000000}{50}x\right)\left(1-\frac{\frac{3x}{10}}{100}\right)+500\left(1+\frac{6x}{100}\right)\times 4\times 20\left(1-\frac{\frac{x}{4}}{100}\right)=100\left(20\left(1+\frac{2x}{100}\right)\times 25+5\left(1+\frac{6x}{100}\right)\times 4\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

20000 lortzeko, zatitu 1000000 50 balioarekin.

$$\left(1000000+20000x\right)\left(1-\frac{\frac{3x}{10}}{100}\right)+500\left(1+\frac{6x}{100}\right)\times 4\times 20\left(1-\frac{\frac{x}{4}}{100}\right)=100\left(20\left(1+\frac{2x}{100}\right)\times 25+5\left(1+\frac{6x}{100}\right)\times 4\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

Aplikatu banaketa-propietatea, 1000000+20000x funtzioaren gaiak 1-\frac{\frac{3x}{10}}{100} funtzioaren gaiekin biderkatuz.

$$1000000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+20000x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+500\left(1+\frac{6x}{100}\right)\times 4\times 20\left(1-\frac{\frac{x}{4}}{100}\right)=100\left(20\left(1+\frac{2x}{100}\right)\times 25+5\left(1+\frac{6x}{100}\right)\times 4\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

\frac{3}{50}x lortzeko, zatitu 6x 100 balioarekin.

$$1000000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+20000x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+500\left(1+\frac{3}{50}x\right)\times 4\times 20\left(1-\frac{\frac{x}{4}}{100}\right)=100\left(20\left(1+\frac{2x}{100}\right)\times 25+5\left(1+\frac{6x}{100}\right)\times 4\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

2000 lortzeko, biderkatu 500 eta 4.

$$1000000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+20000x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+2000\left(1+\frac{3}{50}x\right)\times 20\left(1-\frac{\frac{x}{4}}{100}\right)=100\left(20\left(1+\frac{2x}{100}\right)\times 25+5\left(1+\frac{6x}{100}\right)\times 4\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

40000 lortzeko, biderkatu 2000 eta 20.

$$1000000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+20000x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+40000\left(1+\frac{3}{50}x\right)\left(1-\frac{\frac{x}{4}}{100}\right)=100\left(20\left(1+\frac{2x}{100}\right)\times 25+5\left(1+\frac{6x}{100}\right)\times 4\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

Erabili banaketa-propietatea 40000 eta 1+\frac{3}{50}x biderkatzeko.

$$1000000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+20000x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+\left(40000+40000\times \frac{3}{50}x\right)\left(1-\frac{\frac{x}{4}}{100}\right)=100\left(20\left(1+\frac{2x}{100}\right)\times 25+5\left(1+\frac{6x}{100}\right)\times 4\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

Adierazi 40000\times \frac{3}{50} frakzio bakar gisa.

$$1000000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+20000x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+\left(40000+\frac{40000\times 3}{50}x\right)\left(1-\frac{\frac{x}{4}}{100}\right)=100\left(20\left(1+\frac{2x}{100}\right)\times 25+5\left(1+\frac{6x}{100}\right)\times 4\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

120000 lortzeko, biderkatu 40000 eta 3.

$$1000000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+20000x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+\left(40000+\frac{120000}{50}x\right)\left(1-\frac{\frac{x}{4}}{100}\right)=100\left(20\left(1+\frac{2x}{100}\right)\times 25+5\left(1+\frac{6x}{100}\right)\times 4\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

2400 lortzeko, zatitu 120000 50 balioarekin.

$$1000000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+20000x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+\left(40000+2400x\right)\left(1-\frac{\frac{x}{4}}{100}\right)=100\left(20\left(1+\frac{2x}{100}\right)\times 25+5\left(1+\frac{6x}{100}\right)\times 4\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

Aplikatu banaketa-propietatea, 40000+2400x funtzioaren gaiak 1-\frac{\frac{x}{4}}{100} funtzioaren gaiekin biderkatuz.

$$1000000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+20000x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+40000+40000\left(-\frac{\frac{x}{4}}{100}\right)+2400x+2400x\left(-\frac{\frac{x}{4}}{100}\right)=100\left(20\left(1+\frac{2x}{100}\right)\times 25+5\left(1+\frac{6x}{100}\right)\times 4\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

1040000 lortzeko, gehitu 1000000 eta 40000.

$$1040000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+20000x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+40000\left(-\frac{\frac{x}{4}}{100}\right)+2400x+2400x\left(-\frac{\frac{x}{4}}{100}\right)=100\left(20\left(1+\frac{2x}{100}\right)\times 25+5\left(1+\frac{6x}{100}\right)\times 4\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

22400x lortzeko, konbinatu 20000x eta 2400x.

$$1040000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+22400x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+40000\left(-\frac{\frac{x}{4}}{100}\right)+2400x\left(-\frac{\frac{x}{4}}{100}\right)=100\left(20\left(1+\frac{2x}{100}\right)\times 25+5\left(1+\frac{6x}{100}\right)\times 4\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

\frac{1}{50}x lortzeko, zatitu 2x 100 balioarekin.

$$1040000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+22400x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+40000\left(-\frac{\frac{x}{4}}{100}\right)+2400x\left(-\frac{\frac{x}{4}}{100}\right)=100\left(20\left(1+\frac{1}{50}x\right)\times 25+5\left(1+\frac{6x}{100}\right)\times 4\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

500 lortzeko, biderkatu 20 eta 25.

$$1040000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+22400x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+40000\left(-\frac{\frac{x}{4}}{100}\right)+2400x\left(-\frac{\frac{x}{4}}{100}\right)=100\left(500\left(1+\frac{1}{50}x\right)+5\left(1+\frac{6x}{100}\right)\times 4\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

Erabili banaketa-propietatea 500 eta 1+\frac{1}{50}x biderkatzeko.

$$1040000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+22400x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+40000\left(-\frac{\frac{x}{4}}{100}\right)+2400x\left(-\frac{\frac{x}{4}}{100}\right)=100\left(500+500\times \frac{1}{50}x+5\left(1+\frac{6x}{100}\right)\times 4\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

\frac{500}{50} lortzeko, biderkatu 500 eta \frac{1}{50}.

$$1040000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+22400x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+40000\left(-\frac{\frac{x}{4}}{100}\right)+2400x\left(-\frac{\frac{x}{4}}{100}\right)=100\left(500+\frac{500}{50}x+5\left(1+\frac{6x}{100}\right)\times 4\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

10 lortzeko, zatitu 500 50 balioarekin.

$$1040000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+22400x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+40000\left(-\frac{\frac{x}{4}}{100}\right)+2400x\left(-\frac{\frac{x}{4}}{100}\right)=100\left(500+10x+5\left(1+\frac{6x}{100}\right)\times 4\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

\frac{3}{50}x lortzeko, zatitu 6x 100 balioarekin.

$$1040000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+22400x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+40000\left(-\frac{\frac{x}{4}}{100}\right)+2400x\left(-\frac{\frac{x}{4}}{100}\right)=100\left(500+10x+5\left(1+\frac{3}{50}x\right)\times 4\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

20 lortzeko, biderkatu 5 eta 4.

$$1040000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+22400x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+40000\left(-\frac{\frac{x}{4}}{100}\right)+2400x\left(-\frac{\frac{x}{4}}{100}\right)=100\left(500+10x+20\left(1+\frac{3}{50}x\right)\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

Erabili banaketa-propietatea 20 eta 1+\frac{3}{50}x biderkatzeko.

$$1040000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+22400x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+40000\left(-\frac{\frac{x}{4}}{100}\right)+2400x\left(-\frac{\frac{x}{4}}{100}\right)=100\left(500+10x+20+20\times \frac{3}{50}x\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

Adierazi 20\times \frac{3}{50} frakzio bakar gisa.

$$1040000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+22400x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+40000\left(-\frac{\frac{x}{4}}{100}\right)+2400x\left(-\frac{\frac{x}{4}}{100}\right)=100\left(500+10x+20+\frac{20\times 3}{50}x\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

60 lortzeko, biderkatu 20 eta 3.

$$1040000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+22400x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+40000\left(-\frac{\frac{x}{4}}{100}\right)+2400x\left(-\frac{\frac{x}{4}}{100}\right)=100\left(500+10x+20+\frac{60}{50}x\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

Murriztu \frac{60}{50} zatikia gai txikienera, 10 bakanduta eta ezeztatuta.

$$1040000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+22400x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+40000\left(-\frac{\frac{x}{4}}{100}\right)+2400x\left(-\frac{\frac{x}{4}}{100}\right)=100\left(500+10x+20+\frac{6}{5}x\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

520 lortzeko, gehitu 500 eta 20.

$$1040000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+22400x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+40000\left(-\frac{\frac{x}{4}}{100}\right)+2400x\left(-\frac{\frac{x}{4}}{100}\right)=100\left(520+10x+\frac{6}{5}x\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

\frac{56}{5}x lortzeko, konbinatu 10x eta \frac{6}{5}x.

$$1040000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+22400x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+40000\left(-\frac{\frac{x}{4}}{100}\right)+2400x\left(-\frac{\frac{x}{4}}{100}\right)=100\left(520+\frac{56}{5}x\right)\times 20\left(1-\frac{\frac{5x}{18}}{100}\right)$$

2000 lortzeko, biderkatu 100 eta 20.

$$1040000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+22400x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+40000\left(-\frac{\frac{x}{4}}{100}\right)+2400x\left(-\frac{\frac{x}{4}}{100}\right)=2000\left(520+\frac{56}{5}x\right)\left(1-\frac{\frac{5x}{18}}{100}\right)$$

Erabili banaketa-propietatea 2000 eta 520+\frac{56}{5}x biderkatzeko.

$$1040000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+22400x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+40000\left(-\frac{\frac{x}{4}}{100}\right)+2400x\left(-\frac{\frac{x}{4}}{100}\right)=\left(1040000+2000\times \frac{56}{5}x\right)\left(1-\frac{\frac{5x}{18}}{100}\right)$$

Adierazi 2000\times \frac{56}{5} frakzio bakar gisa.

$$1040000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+22400x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+40000\left(-\frac{\frac{x}{4}}{100}\right)+2400x\left(-\frac{\frac{x}{4}}{100}\right)=\left(1040000+\frac{2000\times 56}{5}x\right)\left(1-\frac{\frac{5x}{18}}{100}\right)$$

112000 lortzeko, biderkatu 2000 eta 56.

$$1040000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+22400x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+40000\left(-\frac{\frac{x}{4}}{100}\right)+2400x\left(-\frac{\frac{x}{4}}{100}\right)=\left(1040000+\frac{112000}{5}x\right)\left(1-\frac{\frac{5x}{18}}{100}\right)$$

22400 lortzeko, zatitu 112000 5 balioarekin.

$$1040000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+22400x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+40000\left(-\frac{\frac{x}{4}}{100}\right)+2400x\left(-\frac{\frac{x}{4}}{100}\right)=\left(1040000+22400x\right)\left(1-\frac{\frac{5x}{18}}{100}\right)$$

Aplikatu banaketa-propietatea, 1040000+22400x funtzioaren gaiak 1-\frac{\frac{5x}{18}}{100} funtzioaren gaiekin biderkatuz.

$$1040000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+22400x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+40000\left(-\frac{\frac{x}{4}}{100}\right)+2400x\left(-\frac{\frac{x}{4}}{100}\right)=1040000+1040000\left(-\frac{\frac{5x}{18}}{100}\right)+22400x+22400x\left(-\frac{\frac{5x}{18}}{100}\right)$$

Kendu 1040000\left(-\frac{\frac{5x}{18}}{100}\right) bi aldeetatik.

$$1040000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+22400x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+40000\left(-\frac{\frac{x}{4}}{100}\right)+2400x\left(-\frac{\frac{x}{4}}{100}\right)-1040000\left(-\frac{\frac{5x}{18}}{100}\right)=1040000+22400x+22400x\left(-\frac{\frac{5x}{18}}{100}\right)$$

Kendu 22400x bi aldeetatik.

$$1040000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+22400x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+40000\left(-\frac{\frac{x}{4}}{100}\right)+2400x\left(-\frac{\frac{x}{4}}{100}\right)-1040000\left(-\frac{\frac{5x}{18}}{100}\right)-22400x=1040000+22400x\left(-\frac{\frac{5x}{18}}{100}\right)$$

Kendu 22400x\left(-\frac{\frac{5x}{18}}{100}\right) bi aldeetatik.

$$1040000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+22400x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+40000\left(-\frac{\frac{x}{4}}{100}\right)+2400x\left(-\frac{\frac{x}{4}}{100}\right)-1040000\left(-\frac{\frac{5x}{18}}{100}\right)-22400x-22400x\left(-\frac{\frac{5x}{18}}{100}\right)=1040000$$

Biderkatu ekuazioaren bi aldeak honekin: 100.

$$100\left(1040000+1000000\left(-\frac{\frac{3x}{10}}{100}\right)+22400x+20000x\left(-\frac{\frac{3x}{10}}{100}\right)+40000\left(-\frac{\frac{x}{4}}{100}\right)+2400x\left(-\frac{\frac{x}{4}}{100}\right)-1040000\left(-\frac{\frac{5x}{18}}{100}\right)-22400x\right)-2240000x\left(-\frac{\frac{5x}{18}}{100}\right)=104000000$$

Berrantolatu gaiak.

$$100\left(2400x\left(-\frac{x}{4\times 100}\right)+20000x\left(-\frac{3x}{10\times 100}\right)+40000\left(-\frac{x}{4\times 100}\right)+1000000\left(-\frac{3x}{10\times 100}\right)+22400x+1040000-1040000\left(-\frac{5x}{18\times 100}\right)-22400x\right)-2240000x\left(-\frac{5x}{18\times 100}\right)=104000000$$

-40000 lortzeko, biderkatu 40000 eta -1. -1000000 lortzeko, biderkatu 1000000 eta -1. -1040000 lortzeko, biderkatu -1 eta 1040000.

$$100\left(2400x\left(-1\right)\times \frac{x}{4\times 100}+20000x\left(-1\right)\times \frac{3x}{10\times 100}-40000\times \frac{x}{4\times 100}-1000000\times \frac{3x}{10\times 100}+22400x+1040000-1040000\left(-1\right)\times \frac{5x}{18\times 100}-22400x\right)-2240000x\left(-1\right)\times \frac{5x}{18\times 100}=104000000$$

-2400 lortzeko, biderkatu 2400 eta -1.

$$100\left(-2400x\times \frac{x}{4\times 100}+20000x\left(-1\right)\times \frac{3x}{10\times 100}-40000\times \frac{x}{4\times 100}-1000000\times \frac{3x}{10\times 100}+22400x+1040000-1040000\left(-1\right)\times \frac{5x}{18\times 100}-22400x\right)-2240000x\left(-1\right)\times \frac{5x}{18\times 100}=104000000$$

400 lortzeko, biderkatu 4 eta 100.

$$100\left(-2400x\times \frac{x}{400}+20000x\left(-1\right)\times \frac{3x}{10\times 100}-40000\times \frac{x}{4\times 100}-1000000\times \frac{3x}{10\times 100}+22400x+1040000-1040000\left(-1\right)\times \frac{5x}{18\times 100}-22400x\right)-2240000x\left(-1\right)\times \frac{5x}{18\times 100}=104000000$$

Deuseztatu 2400 eta 400 balioen faktore komunetan handiena (400).

$$100\left(-6xx+20000x\left(-1\right)\times \frac{3x}{10\times 100}-40000\times \frac{x}{4\times 100}-1000000\times \frac{3x}{10\times 100}+22400x+1040000-1040000\left(-1\right)\times \frac{5x}{18\times 100}-22400x\right)-2240000x\left(-1\right)\times \frac{5x}{18\times 100}=104000000$$

-20000 lortzeko, biderkatu 20000 eta -1.

$$100\left(-6xx-20000x\times \frac{3x}{10\times 100}-40000\times \frac{x}{4\times 100}-1000000\times \frac{3x}{10\times 100}+22400x+1040000-1040000\left(-1\right)\times \frac{5x}{18\times 100}-22400x\right)-2240000x\left(-1\right)\times \frac{5x}{18\times 100}=104000000$$

1000 lortzeko, biderkatu 10 eta 100.

$$100\left(-6xx-20000x\times \frac{3x}{1000}-40000\times \frac{x}{4\times 100}-1000000\times \frac{3x}{10\times 100}+22400x+1040000-1040000\left(-1\right)\times \frac{5x}{18\times 100}-22400x\right)-2240000x\left(-1\right)\times \frac{5x}{18\times 100}=104000000$$

Deuseztatu 20000 eta 1000 balioen faktore komunetan handiena (1000).

$$100\left(-6xx-20\times 3xx-40000\times \frac{x}{4\times 100}-1000000\times \frac{3x}{10\times 100}+22400x+1040000-1040000\left(-1\right)\times \frac{5x}{18\times 100}-22400x\right)-2240000x\left(-1\right)\times \frac{5x}{18\times 100}=104000000$$

400 lortzeko, biderkatu 4 eta 100.

$$100\left(-6xx-20\times 3xx-40000\times \frac{x}{400}-1000000\times \frac{3x}{10\times 100}+22400x+1040000-1040000\left(-1\right)\times \frac{5x}{18\times 100}-22400x\right)-2240000x\left(-1\right)\times \frac{5x}{18\times 100}=104000000$$

Deuseztatu 40000 eta 400 balioen faktore komunetan handiena (400).

$$100\left(-6xx-20\times 3xx-100x-1000000\times \frac{3x}{10\times 100}+22400x+1040000-1040000\left(-1\right)\times \frac{5x}{18\times 100}-22400x\right)-2240000x\left(-1\right)\times \frac{5x}{18\times 100}=104000000$$

1000 lortzeko, biderkatu 10 eta 100.

$$100\left(-6xx-20\times 3xx-100x-1000000\times \frac{3x}{1000}+22400x+1040000-1040000\left(-1\right)\times \frac{5x}{18\times 100}-22400x\right)-2240000x\left(-1\right)\times \frac{5x}{18\times 100}=104000000$$

Deuseztatu 1000000 eta 1000 balioen faktore komunetan handiena (1000).

$$100\left(-6xx-20\times 3xx-100x-1000\times 3x+22400x+1040000-1040000\left(-1\right)\times \frac{5x}{18\times 100}-22400x\right)-2240000x\left(-1\right)\times \frac{5x}{18\times 100}=104000000$$

22300x lortzeko, konbinatu -100x eta 22400x.

$$100\left(-6xx-20\times 3xx+22300x-1000\times 3x+1040000-1040000\left(-1\right)\times \frac{5x}{18\times 100}-22400x\right)-2240000x\left(-1\right)\times \frac{5x}{18\times 100}=104000000$$

1040000 lortzeko, biderkatu -1040000 eta -1.

$$100\left(-6xx-20\times 3xx+22300x-1000\times 3x+1040000+1040000\times \frac{5x}{18\times 100}-22400x\right)-2240000x\left(-1\right)\times \frac{5x}{18\times 100}=104000000$$

Sinplifikatu 5 zenbakitzailean eta izendatzailean.

$$100\left(-6xx-20\times 3xx+22300x-1000\times 3x+1040000+1040000\times \frac{x}{18\times 20}-22400x\right)-2240000x\left(-1\right)\times \frac{5x}{18\times 100}=104000000$$

360 lortzeko, biderkatu 18 eta 20.

$$100\left(-6xx-20\times 3xx+22300x-1000\times 3x+1040000+1040000\times \frac{x}{360}-22400x\right)-2240000x\left(-1\right)\times \frac{5x}{18\times 100}=104000000$$

Adierazi 1040000\times \frac{x}{360} frakzio bakar gisa.

$$100\left(-6xx-20\times 3xx+22300x-1000\times 3x+1040000+\frac{1040000x}{360}-22400x\right)-2240000x\left(-1\right)\times \frac{5x}{18\times 100}=104000000$$

-100x lortzeko, konbinatu 22300x eta -22400x.

$$100\left(-6xx-20\times 3xx-100x-1000\times 3x+1040000+\frac{1040000x}{360}\right)-2240000x\left(-1\right)\times \frac{5x}{18\times 100}=104000000$$

-60 lortzeko, biderkatu -20 eta 3. -3000 lortzeko, biderkatu -1000 eta 3.

$$100\left(-6xx-60xx-100x-3000x+1040000+\frac{1040000x}{360}\right)-2240000x\left(-1\right)\times \frac{5x}{18\times 100}=104000000$$

-66xx lortzeko, konbinatu -6xx eta -60xx.

$$100\left(-66xx-100x-3000x+1040000+\frac{1040000x}{360}\right)-2240000x\left(-1\right)\times \frac{5x}{18\times 100}=104000000$$

-3100x lortzeko, konbinatu -100x eta -3000x.

$$100\left(-66xx-3100x+1040000+\frac{1040000x}{360}\right)-2240000x\left(-1\right)\times \frac{5x}{18\times 100}=104000000$$

Erabili banaketa-propietatea 100 eta -66xx-3100x+1040000+\frac{1040000x}{360} biderkatzeko.

$$-6600x^{2}-310000x+104000000+100\times \frac{1040000x}{360}-2240000x\left(-1\right)\times \frac{5x}{18\times 100}=104000000$$

\frac{26000}{9}x lortzeko, zatitu 1040000x 360 balioarekin.

$$-6600x^{2}-310000x+104000000+100\times \frac{26000}{9}x-2240000x\left(-1\right)\times \frac{5x}{18\times 100}=104000000$$

Adierazi 100\times \frac{26000}{9} frakzio bakar gisa.

$$-6600x^{2}-310000x+104000000+\frac{100\times 26000}{9}x-2240000x\left(-1\right)\times \frac{5x}{18\times 100}=104000000$$

2600000 lortzeko, biderkatu 100 eta 26000.

$$-6600x^{2}-310000x+104000000+\frac{2600000}{9}x-2240000x\left(-1\right)\times \frac{5x}{18\times 100}=104000000$$

-\frac{190000}{9}x lortzeko, konbinatu -310000x eta \frac{2600000}{9}x.

$$-6600x^{2}-\frac{190000}{9}x+104000000-2240000x\left(-1\right)\times \frac{5x}{18\times 100}=104000000$$

2240000 lortzeko, biderkatu -2240000 eta -1.

$$-6600x^{2}-\frac{190000}{9}x+104000000+2240000x\times \frac{5x}{18\times 100}=104000000$$

Sinplifikatu 5 zenbakitzailean eta izendatzailean.

$$-6600x^{2}-\frac{190000}{9}x+104000000+2240000x\times \frac{x}{18\times 20}=104000000$$

360 lortzeko, biderkatu 18 eta 20.

$$-6600x^{2}-\frac{190000}{9}x+104000000+2240000x\times \frac{x}{360}=104000000$$

Adierazi 2240000\times \frac{x}{360} frakzio bakar gisa.

$$-6600x^{2}-\frac{190000}{9}x+104000000+\frac{2240000x}{360}x=104000000$$

\frac{56000}{9}x lortzeko, zatitu 2240000x 360 balioarekin.

$$-6600x^{2}-\frac{190000}{9}x+104000000+\frac{56000}{9}xx=104000000$$

x^{2} lortzeko, biderkatu x eta x.

$$-6600x^{2}-\frac{190000}{9}x+104000000+\frac{56000}{9}x^{2}=104000000$$

-\frac{3400}{9}x^{2} lortzeko, konbinatu -6600x^{2} eta \frac{56000}{9}x^{2}.

$$-\frac{3400}{9}x^{2}-\frac{190000}{9}x+104000000=104000000$$

Kendu 104000000 bi aldeetatik.

$$-\frac{3400}{9}x^{2}-\frac{190000}{9}x=104000000-104000000$$

0 lortzeko, 104000000 balioari kendu 104000000.

$$-\frac{3400}{9}x^{2}-\frac{190000}{9}x=0$$

Zatitu ekuazioaren bi aldeak -\frac{3400}{9} balioarekin. Bi aldeak frakzioaren frakzio erreziprokoarekin biderkatzearen berdina da.

$$\frac{-\frac{3400}{9}x^{2}-\frac{190000}{9}x}{-\frac{3400}{9}}=\frac{0}{-\frac{3400}{9}}$$

-\frac{3400}{9} balioarekin zatituz gero, -\frac{3400}{9} balioarekiko biderketa desegiten da.

$$x^{2}+\left(-\frac{\frac{190000}{9}}{-\frac{3400}{9}}\right)x=\frac{0}{-\frac{3400}{9}}$$

Zatitu -\frac{190000}{9} balioa -\frac{3400}{9} frakzioarekin, -\frac{190000}{9} balioa -\frac{3400}{9} frakzioaren frakzio erreziprokoarekin biderkatuz.

$$x^{2}+\frac{950}{17}x=\frac{0}{-\frac{3400}{9}}$$

Zatitu 0 balioa -\frac{3400}{9} frakzioarekin, 0 balioa -\frac{3400}{9} frakzioaren frakzio erreziprokoarekin biderkatuz.

$$x^{2}+\frac{950}{17}x=0$$

Zatitu \frac{950}{17} (x gaiaren koefizientea) 2 balioarekin, eta \frac{475}{17} lortuko duzu. Ondoren, gehitu \frac{475}{17} balioaren karratua ekuazioaren bi aldeetan. Horrela, ekuazioaren ezkerreko zatia karratu perfektua izango da.

$$x^{2}+\frac{950}{17}x+\left(\frac{475}{17}\right)^{2}=\left(\frac{475}{17}\right)^{2}$$

Egin \frac{475}{17} ber bi, frakzioaren zenbakitzailea eta izendatzailea ber bi eginez.

$$x^{2}+\frac{950}{17}x+\frac{225625}{289}=\frac{225625}{289}$$

Atera x^{2}+\frac{950}{17}x+\frac{225625}{289} balioaren biderkagaiak. Orokorrean, x^{2}+bx+c karratu perfektua bada, \left(x+\frac{b}{2}\right)^{2} gisa ateratzen dira biderkagaiak.

$$\left(x+\frac{475}{17}\right)^{2}=\frac{225625}{289}$$

Atera ekuazioaren bi aldeen erro karratua.

$$\sqrt{\left(x+\frac{475}{17}\right)^{2}}=\sqrt{\frac{225625}{289}}$$

Sinplifikatu.

$$x+\frac{475}{17}=\frac{475}{17} x+\frac{475}{17}=-\frac{475}{17}$$

Egin ken \frac{475}{17} ekuazioaren bi aldeetan.

$$x=0 x=-\frac{950}{17}$$