Lahenda a^{5}b^{7}(a+b)^9+4a^6b^6(a+b)^7 | Microsofti matemaatika lahendaja

Arvuta

\left(b\left(a+b\right)^{2}+4a\right)a^{5}b^{6}\left(a+b\right)^{7}

Laienda

126a^{10}b^{11}+126a^{9}b^{12}+140a^{9}b^{10}+84a^{8}b^{13}+84a^{8}b^{11}+36a^{7}b^{14}+28a^{7}b^{12}+9a^{6}b^{15}+4a^{6}b^{13}+a^{5}b^{16}+84b^{10}a^{11}+36b^{9}a^{12}+140b^{9}a^{10}+9b^{8}a^{13}+84b^{8}a^{11}+b^{7}a^{14}+28b^{7}a^{12}+4b^{6}a^{13}

Viktoriin

Algebra

a ^ { 5 } b ^ { 7 } ( a + b ) ^ { 9 } + 4 a ^ { 6 } b ^ { 6 } ( a + b ) ^ { 7 }

Sarnased probleemid veebiotsingust

4a^7b^2+10a^5b^3-7a^3b^4

https://www.tiger-algebra.com/drill/4a~7b~2_10a~5b~3-7a~3b~4/

4a7b2+10a5b3-7a3b4 Final result : a3b2 • (4a4 + 10a2b - 7b2) Step by step solution : Step 1 :Equation at the end of step 1 : (((4•(a7))•(b2))+((10•(a5))•(b3)))-(7a3•b4) Step 2 :Equation at the ...

2a^5b^2+8a^4b^3-4a^3b^4

http://www.tiger-algebra.com/drill/2a~5b~2_8a~4b~3-4a~3b~4/

2a5b2+8a4b3-4a3b4 Final result : 2a3b2 • (a2 + 4ab - 2b2) Step by step solution : Step 1 :Equation at the end of step 1 : (((2•(a5))•(b2))+((8•(a4))•(b3)))-(22a3•b4) Step 2 :Equation at the ...

6a^4b^2-11a^3b^3+4a^2b^2

https://www.tiger-algebra.com/drill/6a~4b~2-11a~3b~3_4a~2b~2/

6a4b2-11a3b3+4a2b2 Final result : a2b2 • (6a2 - 11ab + 4) Step by step solution : Step 1 :Equation at the end of step 1 : (((6•(a4))•(b2))-((11•(a3))•(b3)))+(22a2•b2) Step 2 :Equation at the ...

How do you multiply \displaystyle{\left({3}{a}^{{{5}}}{b}^{{{3}}}{c}^{{{3}}}\right)}^{{{2}}}{\left({2}{a}^{{{2}}}{b}^{{{5}}}{c}^{{{4}}}\right)}^{{{3}}} ?

https://socratic.org/questions/how-do-you-multiply-3a-5-b-3-c-3-2-2a-2-b-5-c-4-3

Multiply and then add the exponents. Explanation: We have: \displaystyle{f}={\left({3}{a}^{{5}}{b}^{{3}}{c}^{{3}}\right)}^{{2}}{\left({2}{a}^{{2}}{b}^{{5}}{c}^{{4}}\right)}^{{3}} Given that \displaystyle{\left({a}^{{5}}\right)}^{{2}}={a}^{{{10}}} ...

If a, b and c are sides of a triangle, then prove that a^\text{2}(b+c-a) + b^\text{2}(c+a-b) + c^\text{2}(a+b-c) \leqslant 3abc

https://math.stackexchange.com/questions/3117833/if-a-b-and-c-are-sides-of-a-triangle-then-prove-that-a-text2bc-a

It's true for all non-negatives a , b and c . Indeed, since our inequality is symmetric, we can assume that a\geq b\geq c and we obtain: 3abc-\sum_{cyc}a^2(b+c-a)=\sum_{cyc}(a^3-a^2b-a^2c+abc)=\sum_{cyc}a(a-b)(a-c)\geq ...

DFA/NDFA problems confirmation

https://math.stackexchange.com/q/1372108

Your first answer is now correct. Your second shows that you understand what the language is, but your notation is incorrect. L_1 is a set of words; your expression is not a set, and it uses the ...

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{ x } ^ { 2 } - 4 x - 5 = 0

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\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]

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\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.

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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }

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\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x

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\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}

Teemad

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