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17\left(20^{2}+\left(15t\right)^{2}-\left(12+15t\right)^{2}\right)=-10\left(34^{2}+\left(15t\right)^{2}-\left(30+15t\right)^{2}\right)
Muutuja t ei tohi võrduda väärtusega 0, kuna nulliga jagamist pole määratletud. Korrutage võrrandi mõlemad pooled arvuga 1020t, mis on arvu 60t,-102t vähim ühiskordne.
17\left(400+\left(15t\right)^{2}-\left(12+15t\right)^{2}\right)=-10\left(34^{2}+\left(15t\right)^{2}-\left(30+15t\right)^{2}\right)
Arvutage 2 aste 20 ja leidke 400.
17\left(400+15^{2}t^{2}-\left(12+15t\right)^{2}\right)=-10\left(34^{2}+\left(15t\right)^{2}-\left(30+15t\right)^{2}\right)
Laiendage \left(15t\right)^{2}.
17\left(400+225t^{2}-\left(12+15t\right)^{2}\right)=-10\left(34^{2}+\left(15t\right)^{2}-\left(30+15t\right)^{2}\right)
Arvutage 2 aste 15 ja leidke 225.
17\left(400+225t^{2}-\left(144+360t+225t^{2}\right)\right)=-10\left(34^{2}+\left(15t\right)^{2}-\left(30+15t\right)^{2}\right)
Kasutage kaksliikme \left(12+15t\right)^{2} arendamiseks binoomvalemit \left(a+b\right)^{2}=a^{2}+2ab+b^{2}.
17\left(400+225t^{2}-144-360t-225t^{2}\right)=-10\left(34^{2}+\left(15t\right)^{2}-\left(30+15t\right)^{2}\right)
Avaldise "144+360t+225t^{2}" vastandi leidmiseks tuleb leida iga liikme vastand.
17\left(256+225t^{2}-360t-225t^{2}\right)=-10\left(34^{2}+\left(15t\right)^{2}-\left(30+15t\right)^{2}\right)
Lahutage 144 väärtusest 400, et leida 256.
17\left(256-360t\right)=-10\left(34^{2}+\left(15t\right)^{2}-\left(30+15t\right)^{2}\right)
Kombineerige 225t^{2} ja -225t^{2}, et leida 0.
4352-6120t=-10\left(34^{2}+\left(15t\right)^{2}-\left(30+15t\right)^{2}\right)
Kasutage distributiivsusomadust, et korrutada 17 ja 256-360t.
4352-6120t=-10\left(1156+\left(15t\right)^{2}-\left(30+15t\right)^{2}\right)
Arvutage 2 aste 34 ja leidke 1156.
4352-6120t=-10\left(1156+15^{2}t^{2}-\left(30+15t\right)^{2}\right)
Laiendage \left(15t\right)^{2}.
4352-6120t=-10\left(1156+225t^{2}-\left(30+15t\right)^{2}\right)
Arvutage 2 aste 15 ja leidke 225.
4352-6120t=-10\left(1156+225t^{2}-\left(900+900t+225t^{2}\right)\right)
Kasutage kaksliikme \left(30+15t\right)^{2} arendamiseks binoomvalemit \left(a+b\right)^{2}=a^{2}+2ab+b^{2}.
4352-6120t=-10\left(1156+225t^{2}-900-900t-225t^{2}\right)
Avaldise "900+900t+225t^{2}" vastandi leidmiseks tuleb leida iga liikme vastand.
4352-6120t=-10\left(256+225t^{2}-900t-225t^{2}\right)
Lahutage 900 väärtusest 1156, et leida 256.
4352-6120t=-10\left(256-900t\right)
Kombineerige 225t^{2} ja -225t^{2}, et leida 0.
4352-6120t=-2560+9000t
Kasutage distributiivsusomadust, et korrutada -10 ja 256-900t.
4352-6120t-9000t=-2560
Lahutage mõlemast poolest 9000t.
4352-15120t=-2560
Kombineerige -6120t ja -9000t, et leida -15120t.
-15120t=-2560-4352
Lahutage mõlemast poolest 4352.
-15120t=-6912
Lahutage 4352 väärtusest -2560, et leida -6912.
t=\frac{-6912}{-15120}
Jagage mõlemad pooled -15120-ga.
t=\frac{16}{35}
Taandage murd \frac{-6912}{-15120} vähimale ühiskordsele, eraldades ja taandades arvu -432.