Solve dx/dy | Microsoft Math Solver

d x / d y

Evaluate

x y

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Differentiate w.r.t. x

y

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5 problems similar to:

d x / d y

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Orthogonal trajectory of

x y = 2

https://math.stackexchange.com/q/1949337

I'm not sure what you mean by "give the correct ans". So I'll solve both equations: (1) If

\frac{d y}{d x} = - \frac{y}{x}

, then the orthogonal trajectory satisfies

\frac{d y}{d x} = \frac{x}{y}

Simple Derivative paradox

https://math.stackexchange.com/questions/911617/simple-derivative-paradox

\frac{d x}{d y}

0

x = y^{1 / 3}

\frac{d x}{d y} = \frac{1}{3} y^{- 2 / 3} = \frac{1}{3 x ^{2}}

. The same sort of argument holds for arbitrary

y (x)

(modulo being ...

How to solve the following differential equation:

x y^{'} - y = (x + y) (ln (x + y) - ln (x))

https://math.stackexchange.com/questions/129289/how-to-solve-the-following-differential-equation-xy-y-xy-lnxy-lnx

x y^{'} - y = (x + y) (lo g (x + y) - lo g (x))

upon dividing by

x^{2}

[1 + \frac{y}{x}]^{'} = \frac{1}{x} (1 + \frac{y}{x}) lo g (1 + \frac{y}{x})

z = 1 + y / x

Definition of reciprocal derivative

https://math.stackexchange.com/questions/913333/definition-of-reciprocal-derivative

What you see is abuse of notation, in a way. Here,

x

y

are both variables, but we have an equation relating them to each other, so we think of them as functions of each other. If we define the ...

Integrating factor O.D.E.

https://math.stackexchange.com/questions/2384136/integrating-factor-o-d-e

Using the integrating factor method

P (x) = 3 x^{2}

and therefore the integrating factor is

e^{x^{3}}

, multiplying both sides by this we get

e^{x^{3}} y^{'} + 3 x^{2} e^{x^{3}} y = x^{2} e^{x^{3}} ⟹ (e^{x^{3}} y)^{'} = x^{2} e^{x^{3}}

Finding derivatives for a Cauchy-Euler ODE

https://math.stackexchange.com/questions/1220987/finding-derivatives-for-a-cauchy-euler-ode

Well, here we have a classic case of "forgot to write all variables, got a ton of questions". Short answer - we don't cancel the factors (as in red), we use the derivative of composite function. Long ...

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xy

Cancel out d in both numerator and denominator.

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