Solve z=(4-x-y^2)

$$z=(4-x- { y }^{ 2 } )$$

Solve for x

$$x=4-z-y^{2}$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$4-x-y^{2}=z$$

Subtract 4 from both sides.

$$-x-y^{2}=z-4$$

Add y^{2} to both sides.

$$-x=z-4+y^{2}$$

The equation is in standard form.

$$-x=y^{2}+z-4$$

Divide both sides by -1.

$$\frac{-x}{-1}=\frac{y^{2}+z-4}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$x=\frac{y^{2}+z-4}{-1}$$

Divide z-4+y^{2} by -1.

$$x=4-z-y^{2}$$

Solve for y (complex solution)

$$y=-\sqrt{4-z-x}$$

$$y=\sqrt{4-z-x}$$

Solve for y

$$y=\sqrt{4-z-x}$$

$$y=-\sqrt{4-z-x}\text{, }z\leq 4-x$$