Solve for z
z=-1-i
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z=\frac{1-i}{i}
Divide both sides by i.
z=\frac{\left(1-i\right)i}{1i^{2}}
Multiply both numerator and denominator of \frac{1-i}{i} by imaginary unit i.
z=\frac{\left(1-i\right)i}{-1}
By definition, i^{2} is -1. Calculate the denominator.
z=\frac{i-i^{2}}{-1}
Multiply 1-i times i.
z=\frac{i-\left(-1\right)}{-1}
By definition, i^{2} is -1.
z=\frac{1+i}{-1}
Do the multiplications in i-\left(-1\right). Reorder the terms.
z=-1-i
Divide 1+i by -1 to get -1-i.
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