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z^{2}-24z-8=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
z=\frac{-\left(-24\right)±\sqrt{\left(-24\right)^{2}-4\left(-8\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, -24 for b, and -8 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
z=\frac{-\left(-24\right)±\sqrt{576-4\left(-8\right)}}{2}
Square -24.
z=\frac{-\left(-24\right)±\sqrt{576+32}}{2}
Multiply -4 times -8.
z=\frac{-\left(-24\right)±\sqrt{608}}{2}
Add 576 to 32.
z=\frac{-\left(-24\right)±4\sqrt{38}}{2}
Take the square root of 608.
z=\frac{24±4\sqrt{38}}{2}
The opposite of -24 is 24.
z=\frac{4\sqrt{38}+24}{2}
Now solve the equation z=\frac{24±4\sqrt{38}}{2} when ± is plus. Add 24 to 4\sqrt{38}.
z=2\sqrt{38}+12
Divide 24+4\sqrt{38} by 2.
z=\frac{24-4\sqrt{38}}{2}
Now solve the equation z=\frac{24±4\sqrt{38}}{2} when ± is minus. Subtract 4\sqrt{38} from 24.
z=12-2\sqrt{38}
Divide 24-4\sqrt{38} by 2.
z=2\sqrt{38}+12 z=12-2\sqrt{38}
The equation is now solved.
z^{2}-24z-8=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
z^{2}-24z-8-\left(-8\right)=-\left(-8\right)
Add 8 to both sides of the equation.
z^{2}-24z=-\left(-8\right)
Subtracting -8 from itself leaves 0.
z^{2}-24z=8
Subtract -8 from 0.
z^{2}-24z+\left(-12\right)^{2}=8+\left(-12\right)^{2}
Divide -24, the coefficient of the x term, by 2 to get -12. Then add the square of -12 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
z^{2}-24z+144=8+144
Square -12.
z^{2}-24z+144=152
Add 8 to 144.
\left(z-12\right)^{2}=152
Factor z^{2}-24z+144. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(z-12\right)^{2}}=\sqrt{152}
Take the square root of both sides of the equation.
z-12=2\sqrt{38} z-12=-2\sqrt{38}
Simplify.
z=2\sqrt{38}+12 z=12-2\sqrt{38}
Add 12 to both sides of the equation.
x ^ 2 -24x -8 = 0
Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.
r + s = 24 rs = -8
Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C
r = 12 - u s = 12 + u
Two numbers r and s sum up to 24 exactly when the average of the two numbers is \frac{1}{2}*24 = 12. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>
(12 - u) (12 + u) = -8
To solve for unknown quantity u, substitute these in the product equation rs = -8
144 - u^2 = -8
Simplify by expanding (a -b) (a + b) = a^2 – b^2
-u^2 = -8-144 = -152
Simplify the expression by subtracting 144 on both sides
u^2 = 152 u = \pm\sqrt{152} = \pm \sqrt{152}
Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u
r =12 - \sqrt{152} = -0.329 s = 12 + \sqrt{152} = 24.329
The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.