Solve for z
z=15
z=-15
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z^{2}-225=0
Subtract 225 from both sides.
\left(z-15\right)\left(z+15\right)=0
Consider z^{2}-225. Rewrite z^{2}-225 as z^{2}-15^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
z=15 z=-15
To find equation solutions, solve z-15=0 and z+15=0.
z=15 z=-15
Take the square root of both sides of the equation.
z^{2}-225=0
Subtract 225 from both sides.
z=\frac{0±\sqrt{0^{2}-4\left(-225\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -225 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
z=\frac{0±\sqrt{-4\left(-225\right)}}{2}
Square 0.
z=\frac{0±\sqrt{900}}{2}
Multiply -4 times -225.
z=\frac{0±30}{2}
Take the square root of 900.
z=15
Now solve the equation z=\frac{0±30}{2} when ± is plus. Divide 30 by 2.
z=-15
Now solve the equation z=\frac{0±30}{2} when ± is minus. Divide -30 by 2.
z=15 z=-15
The equation is now solved.
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