Solve for z
z=-i
z=i
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z=i z=-i
The equation is now solved.
z^{2}+1=0
Add 1 to both sides.
z=\frac{0±\sqrt{0^{2}-4}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and 1 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
z=\frac{0±\sqrt{-4}}{2}
Square 0.
z=\frac{0±2i}{2}
Take the square root of -4.
z=i
Now solve the equation z=\frac{0±2i}{2} when ± is plus.
z=-i
Now solve the equation z=\frac{0±2i}{2} when ± is minus.
z=i z=-i
The equation is now solved.
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