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-\frac{2}{3}x+\frac{8}{3}=z
Swap sides so that all variable terms are on the left hand side.
-\frac{2}{3}x=z-\frac{8}{3}
Subtract \frac{8}{3} from both sides.
\frac{-\frac{2}{3}x}{-\frac{2}{3}}=\frac{z-\frac{8}{3}}{-\frac{2}{3}}
Divide both sides of the equation by -\frac{2}{3}, which is the same as multiplying both sides by the reciprocal of the fraction.
x=\frac{z-\frac{8}{3}}{-\frac{2}{3}}
Dividing by -\frac{2}{3} undoes the multiplication by -\frac{2}{3}.
x=-\frac{3z}{2}+4
Divide z-\frac{8}{3} by -\frac{2}{3} by multiplying z-\frac{8}{3} by the reciprocal of -\frac{2}{3}.