Solve for k
k=\frac{z+\left(6-2i\right)}{2}
Solve for z
z=2\left(k+\left(-3+i\right)\right)
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2k-6+2i=z
Swap sides so that all variable terms are on the left hand side.
2k+2i=z+6
Add 6 to both sides.
2k=z+6-2i
Subtract 2i from both sides.
2k=z+\left(6-2i\right)
The equation is in standard form.
\frac{2k}{2}=\frac{z+\left(6-2i\right)}{2}
Divide both sides by 2.
k=\frac{z+\left(6-2i\right)}{2}
Dividing by 2 undoes the multiplication by 2.
k=\frac{z}{2}+\left(3-i\right)
Divide z+\left(6-2i\right) by 2.
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