Solve for w
w=\frac{b^{2}}{2}+z
Solve for b
b=\sqrt{2\left(w-z\right)}
b=-\sqrt{2\left(w-z\right)}\text{, }z\leq w
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z=w-\frac{1}{2}b^{2}
Divide each term of 2w-b^{2} by 2 to get w-\frac{1}{2}b^{2}.
w-\frac{1}{2}b^{2}=z
Swap sides so that all variable terms are on the left hand side.
w=z+\frac{1}{2}b^{2}
Add \frac{1}{2}b^{2} to both sides.
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