Solve yx+z=-8

$$yx+z = -8$$

Solve for x (complex solution)

$$\left\{\begin{matrix}x=-\frac{z+8}{y}\text{, }&y\neq 0\\x\in \mathrm{C}\text{, }&z=-8\text{ and }y=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Subtract z from both sides.

$$yx=-8-z$$

The equation is in standard form.

$$yx=-z-8$$

Divide both sides by y.

$$\frac{yx}{y}=\frac{-z-8}{y}$$

Dividing by y undoes the multiplication by y.

$$x=\frac{-z-8}{y}$$

Divide -8-z by y.

$$x=-\frac{z+8}{y}$$

Solve for y (complex solution)

$$\left\{\begin{matrix}y=-\frac{z+8}{x}\text{, }&x\neq 0\\y\in \mathrm{C}\text{, }&z=-8\text{ and }x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Subtract z from both sides.

$$yx=-8-z$$

The equation is in standard form.

$$xy=-z-8$$

Divide both sides by x.

$$\frac{xy}{x}=\frac{-z-8}{x}$$

Dividing by x undoes the multiplication by x.

$$y=\frac{-z-8}{x}$$

Divide -8-z by x.

$$y=-\frac{z+8}{x}$$

Solve for x

$$\left\{\begin{matrix}x=-\frac{z+8}{y}\text{, }&y\neq 0\\x\in \mathrm{R}\text{, }&z=-8\text{ and }y=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Subtract z from both sides.

$$yx=-8-z$$

The equation is in standard form.

$$yx=-z-8$$

Divide both sides by y.

$$\frac{yx}{y}=\frac{-z-8}{y}$$

Dividing by y undoes the multiplication by y.

$$x=\frac{-z-8}{y}$$

Divide -8-z by y.

$$x=-\frac{z+8}{y}$$

Solve for y

$$\left\{\begin{matrix}y=-\frac{z+8}{x}\text{, }&x\neq 0\\y\in \mathrm{R}\text{, }&z=-8\text{ and }x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Subtract z from both sides.

$$yx=-8-z$$

The equation is in standard form.

$$xy=-z-8$$

Divide both sides by x.

$$\frac{xy}{x}=\frac{-z-8}{x}$$

Dividing by x undoes the multiplication by x.

$$y=\frac{-z-8}{x}$$

Divide -8-z by x.

$$y=-\frac{z+8}{x}$$