Solve y2sqrt{5}=-9x+19

$$y2 \sqrt{ 5 } =-9x+19$$

Solve for x

$$x=\frac{-\sqrt{5}y_{2}+19}{9}$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$-9x+19=y_{2}\sqrt{5}$$

Subtract 19 from both sides.

$$-9x=y_{2}\sqrt{5}-19$$

The equation is in standard form.

$$-9x=\sqrt{5}y_{2}-19$$

Divide both sides by -9.

$$\frac{-9x}{-9}=\frac{\sqrt{5}y_{2}-19}{-9}$$

Dividing by -9 undoes the multiplication by -9.

$$x=\frac{\sqrt{5}y_{2}-19}{-9}$$

Divide y_{2}\sqrt{5}-19 by -9.

$$x=\frac{-\sqrt{5}y_{2}+19}{9}$$

Solve for y_2

$$y_{2}=-\frac{\sqrt{5}\left(9x-19\right)}{5}$$

Steps for Solving Linear Equation

The equation is in standard form.

$$\sqrt{5}y_{2}=19-9x$$

Divide both sides by \sqrt{5}.

$$\frac{\sqrt{5}y_{2}}{\sqrt{5}}=\frac{19-9x}{\sqrt{5}}$$

Dividing by \sqrt{5} undoes the multiplication by \sqrt{5}.

$$y_{2}=\frac{19-9x}{\sqrt{5}}$$

Divide -9x+19 by \sqrt{5}.

$$y_{2}=\frac{\sqrt{5}\left(19-9x\right)}{5}$$