Solve y-3=-2/3(x+3)

$$y-3=- \frac{ 2 }{ 3 } (x+3)$$

Solve for x

$$x=\frac{3-3y}{2}$$

Steps for Solving Linear Equation

Use the distributive property to multiply -\frac{2}{3} by x+3.

$$y-3=-\frac{2}{3}x-2$$

Swap sides so that all variable terms are on the left hand side.

$$-\frac{2}{3}x-2=y-3$$

Add 2 to both sides.

$$-\frac{2}{3}x=y-3+2$$

Add -3 and 2 to get -1.

$$-\frac{2}{3}x=y-1$$

Divide both sides of the equation by -\frac{2}{3}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{-\frac{2}{3}x}{-\frac{2}{3}}=\frac{y-1}{-\frac{2}{3}}$$

Dividing by -\frac{2}{3} undoes the multiplication by -\frac{2}{3}.

$$x=\frac{y-1}{-\frac{2}{3}}$$

Divide y-1 by -\frac{2}{3} by multiplying y-1 by the reciprocal of -\frac{2}{3}.

$$x=\frac{3-3y}{2}$$

Solve for y

$$y=-\frac{2x}{3}+1$$

Solution Steps

Use the distributive property to multiply -\frac{2}{3} by x+3.

$$y-3=-\frac{2}{3}x-2$$

Add 3 to both sides.

$$y=-\frac{2}{3}x-2+3$$

Add -2 and 3 to get 1.

$$y=-\frac{2}{3}x+1$$