Solve y-3=1-3/-1-(-2)left(x-(-2right)

$$y-3 = \frac{ 1-3 }{ -1-(-2) } \left( x-(-2 \right)$$

Solve for x

$$x=\frac{-y-1}{2}$$

Steps for Solving Linear Equation

Subtract 3 from 1 to get -2.

$$y-3=\frac{-2}{-1-\left(-2\right)}\left(x-\left(-2\right)\right)$$

The opposite of -2 is 2.

$$y-3=\frac{-2}{-1+2}\left(x-\left(-2\right)\right)$$

Add -1 and 2 to get 1.

$$y-3=\frac{-2}{1}\left(x-\left(-2\right)\right)$$

Anything divided by one gives itself.

$$y-3=-2\left(x-\left(-2\right)\right)$$

The opposite of -2 is 2.

$$y-3=-2\left(x+2\right)$$

Use the distributive property to multiply -2 by x+2.

$$y-3=-2x-4$$

Swap sides so that all variable terms are on the left hand side.

$$-2x-4=y-3$$

Add 4 to both sides.

$$-2x=y-3+4$$

Add -3 and 4 to get 1.

$$-2x=y+1$$

Divide both sides by -2.

$$\frac{-2x}{-2}=\frac{y+1}{-2}$$

Dividing by -2 undoes the multiplication by -2.

$$x=\frac{y+1}{-2}$$

Divide y+1 by -2.

$$x=\frac{-y-1}{2}$$

Solve for y

$$y=-2x-1$$

Solution Steps

Subtract 3 from 1 to get -2.

$$y-3=\frac{-2}{-1-\left(-2\right)}\left(x-\left(-2\right)\right)$$

The opposite of -2 is 2.

$$y-3=\frac{-2}{-1+2}\left(x-\left(-2\right)\right)$$

Add -1 and 2 to get 1.

$$y-3=\frac{-2}{1}\left(x-\left(-2\right)\right)$$

Anything divided by one gives itself.

$$y-3=-2\left(x-\left(-2\right)\right)$$

The opposite of -2 is 2.

$$y-3=-2\left(x+2\right)$$

Use the distributive property to multiply -2 by x+2.

$$y-3=-2x-4$$

Add 3 to both sides.

$$y=-2x-4+3$$

Add -4 and 3 to get -1.

$$y=-2x-1$$