Solve y=-5^2/2^x+2

$$y=- \frac{ { 5 }^{ 2 } }{ { 2 }^{ } } x+2$$

Solve for x

$$x=\frac{4-2y}{25}$$

Steps for Solving Linear Equation

Calculate 5 to the power of 2 and get 25.

$$y=\left(-\frac{25}{2^{1}}\right)x+2$$

Calculate 2 to the power of 1 and get 2.

$$y=-\frac{25}{2}x+2$$

Swap sides so that all variable terms are on the left hand side.

$$-\frac{25}{2}x+2=y$$

Subtract 2 from both sides.

$$-\frac{25}{2}x=y-2$$

Divide both sides of the equation by -\frac{25}{2}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{-\frac{25}{2}x}{-\frac{25}{2}}=\frac{y-2}{-\frac{25}{2}}$$

Dividing by -\frac{25}{2} undoes the multiplication by -\frac{25}{2}.

$$x=\frac{y-2}{-\frac{25}{2}}$$

Divide y-2 by -\frac{25}{2} by multiplying y-2 by the reciprocal of -\frac{25}{2}.

$$x=\frac{4-2y}{25}$$

Solve for y

$$y=-\frac{25x}{2}+2$$

Solution Steps

Calculate 5 to the power of 2 and get 25.

$$y=\left(-\frac{25}{2^{1}}\right)x+2$$

Calculate 2 to the power of 1 and get 2.

$$y=-\frac{25}{2}x+2$$