Solve y=sqrt{x-2x+1}

$$y= \sqrt{ x-2x+1 }$$

Solve for x

$$x=1-y^{2}$$

$$y\geq 0$$

Steps for Solving Radical Equations

Combine x and -2x to get -x.

$$y=\sqrt{-x+1}$$

Swap sides so that all variable terms are on the left hand side.

$$\sqrt{-x+1}=y$$

Square both sides of the equation.

$$-x+1=y^{2}$$

Subtract 1 from both sides of the equation.

$$-x+1-1=y^{2}-1$$

Subtracting 1 from itself leaves 0.

$$-x=y^{2}-1$$

Divide both sides by -1.

$$\frac{-x}{-1}=\frac{y^{2}-1}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$x=\frac{y^{2}-1}{-1}$$

Divide y^{2}-1 by -1.

$$x=1-y^{2}$$

Solve for x (complex solution)

$$x=1-y^{2}$$

$$arg(y)<\pi \text{ or }y=0$$

Solve for y (complex solution)

$$y=\sqrt{1-x}$$

Solve for y

$$y=\sqrt{1-x}$$

$$x\leq 1$$