Solve y=x+1/x-3

$$y= \frac{ x+1 }{ x-3 }$$

Solve for x

$$x=\frac{3y+1}{y-1}$$

$$y\neq 1$$

Steps for Solving Linear Equation

Variable x cannot be equal to 3 since division by zero is not defined. Multiply both sides of the equation by x-3.

$$y\left(x-3\right)=x+1$$

Use the distributive property to multiply y by x-3.

$$yx-3y=x+1$$

Subtract x from both sides.

$$yx-3y-x=1$$

Add 3y to both sides.

$$yx-x=1+3y$$

Combine all terms containing x.

$$\left(y-1\right)x=1+3y$$

The equation is in standard form.

$$\left(y-1\right)x=3y+1$$

Divide both sides by y-1.

$$\frac{\left(y-1\right)x}{y-1}=\frac{3y+1}{y-1}$$

Dividing by y-1 undoes the multiplication by y-1.

$$x=\frac{3y+1}{y-1}$$

Variable x cannot be equal to 3.

$$x=\frac{3y+1}{y-1}\text{, }x\neq 3$$

Solve for y

$$y=\frac{x+1}{x-3}$$

$$x\neq 3$$