Solve y=4/x-3

$$y= \frac{ 4 }{ x-3 }$$

Solve for x

$$x=3+\frac{4}{y}$$

$$y\neq 0$$

Steps for Solving Linear Equation

Variable x cannot be equal to 3 since division by zero is not defined. Multiply both sides of the equation by x-3.

$$y\left(x-3\right)=4$$

Use the distributive property to multiply y by x-3.

$$yx-3y=4$$

Add 3y to both sides.

$$yx=4+3y$$

The equation is in standard form.

$$yx=3y+4$$

Divide both sides by y.

$$\frac{yx}{y}=\frac{3y+4}{y}$$

Dividing by y undoes the multiplication by y.

$$x=\frac{3y+4}{y}$$

Divide 4+3y by y.

$$x=3+\frac{4}{y}$$

Variable x cannot be equal to 3.

$$x=3+\frac{4}{y}\text{, }x\neq 3$$

Solve for y

$$y=\frac{4}{x-3}$$

$$x\neq 3$$