Solve y=4/12x-5

$$y= \frac{ 4 }{ 12x-5 }$$

Solve for x

$$x=\frac{5}{12}+\frac{1}{3y}$$

$$y\neq 0$$

Steps for Solving Linear Equation

Variable x cannot be equal to \frac{5}{12} since division by zero is not defined. Multiply both sides of the equation by 12x-5.

$$y\left(12x-5\right)=4$$

Use the distributive property to multiply y by 12x-5.

$$12yx-5y=4$$

Add 5y to both sides.

$$12yx=4+5y$$

The equation is in standard form.

$$12yx=5y+4$$

Divide both sides by 12y.

$$\frac{12yx}{12y}=\frac{5y+4}{12y}$$

Dividing by 12y undoes the multiplication by 12y.

$$x=\frac{5y+4}{12y}$$

Divide 4+5y by 12y.

$$x=\frac{5}{12}+\frac{1}{3y}$$

Variable x cannot be equal to \frac{5}{12}.

$$x=\frac{5}{12}+\frac{1}{3y}\text{, }x\neq \frac{5}{12}$$

Solve for y

$$y=\frac{4}{12x-5}$$

$$x\neq \frac{5}{12}$$